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找到约 10,000 项符合「融合程序」的源代码

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热门代码： main.c GPIO I2C SPI UART timer interrupt ADC PWM LED
www.eeworm.com/read/127418/14356017

doc 程序.doc

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www.eeworm.com/read/225832/14513925

c 程序.c

#include unsigned char i,j,t,m,DelayTime,DispBuf[3]; //单片机脉搏测量仪源程序 //作者:吴汉清 ntwhq@tom.com unsigned int n,mb; unsigned char code BitTab[3]={0xf7,0xef,0xdf};//位驱动码 unsigned char code D
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www.eeworm.com/read/225832/14513928

c 程序.c

#include unsigned char i,j,t,m,DelayTime,DispBuf[3]; //单片机脉搏测量仪源程序 //作者:吴汉清 ntwhq@tom.com unsigned int n,mb; unsigned char code BitTab[3]={0xf7,0xef,0xdf};//位驱动码 unsigned char code D
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www.eeworm.com/read/221621/14735266

程序说明

这个程序作为无线通讯接收端测试用 将远端送来的4个通道的采集数据送给上位机显示。 接收一个数据包共8个字节。
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www.eeworm.com/read/219690/14870054

txt 程序.txt

library ieee; use ieee.std_logic_1164.all; use ieee.std_logic_unsigned.all; entity szz is port(clk:in std_logic; clk1:in std_logic; md1:in std_logic; md2:in std_logic_vector
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www.eeworm.com/read/117716/14907593

txt 程序.txt

1. 递归方法 int C(int i, int j) { //返回c(i,j) 且计算k(i,j) = kay[i][j] if (i==j) return 0; //一个矩阵的情形 if (i == j-1) { //两个矩阵的情形 kay[i][i+1]=i; return r[i]*r[i+1]*r[i+2]; } //多于两个矩阵的情形 //设u为
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www.eeworm.com/read/213987/15118807

txt 程序.txt

#include #include #define uchar unsigned char #define uint unsigned int #define C8155 XBYTE[0x7000] #define PA XBYTE[0x7001] #define PB XBYTE[0x7002] #define PC XBYTE[0x700
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www.eeworm.com/read/213984/15118813

txt 程序.txt

#include #include #define uchar unsigned char #define uint unsigned int //============================ #define C8155 XBYTE[0x7000] #define PA XBYTE[0x7001] #define PB XBYTE
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www.eeworm.com/read/212886/15146078

doc 程序.doc

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www.eeworm.com/read/211646/15176204

fxp 程序.fxp

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