代码搜索：线阵
找到约 9,846 项符合「线阵」的源代码
代码结果 9,846
www.eeworm.com/read/469138/6978160
txt 子阵和.txt
//求sum{a[0..m-1][0..n-1]}
//维护和查询复杂度均为O(logm*logn)
//用于动态求子阵和,数组内容保存在sum.a[][]中
//可以改成其他数据类型
//query,i行，j列
#include
#define lowbit(x) ((x)&((x)^((x)-1)))
#define MAXN 100
typedef in
www.eeworm.com/read/460783/7240727
txt 子阵和.txt
//求sum{a[0..m-1][0..n-1]}
//维护和查询复杂度均为O(logm*logn)
//用于动态求子阵和,数组内容保存在sum.a[][]中
//可以改成其他数据类型
#include
#define lowbit(x) ((x)&((x)^((x)-1)))
#define MAXN 100
typedef int elem_t;
st
www.eeworm.com/read/457804/7317598
txt 子阵和.txt
//求sum{a[0..m-1][0..n-1]}
//维护和查询复杂度均为O(logm*logn)
//用于动态求子阵和,数组内容保存在sum.a[][]中
//可以改成其他数据类型
#include
#define lowbit(x) ((x)&((x)^((x)-1)))
#define MAXN 100
typedef int elem_t;
st
www.eeworm.com/read/450798/7476649
c 简单逆阵.c
# include "stdio.h"
# define M 3
void main ( )
{
float MAT[M][2*M];
float MAT1[M][M];
float t;
int i,j,k,l;
/***********************************************/
www.eeworm.com/read/450507/7482926
c 简单逆阵.c
# include "stdio.h"
# define M 3
void main ( )
{
float MAT[M][2*M];
float MAT1[M][M];
float t;
int i,j,k,l;
/***********************************************/
www.eeworm.com/read/449694/7497936
c 简单逆阵.c
# include "stdio.h"
# define M 3
void main ( )
{
float MAT[M][2*M];
float MAT1[M][M];
float t;
int i,j,k,l;
/***********************************************/
www.eeworm.com/read/298817/7933209
c 简单逆阵.c
# include "stdio.h"
# define M 3
void main ( )
{
float MAT[M][2*M];
float MAT1[M][M];
float t;
int i,j,k,l;
/***********************************************/
www.eeworm.com/read/197077/8032007
txt 子阵和.txt
//求sum{a[0..m-1][0..n-1]}
//维护和查询复杂度均为O(logm*logn)
//用于动态求子阵和,数组内容保存在sum.a[][]中
//可以改成其他数据类型
#include
#define lowbit(x) ((x)&((x)^((x)-1)))
#define MAXN 100
typedef int elem_t;
st
www.eeworm.com/read/332124/12777168
c 简单逆阵.c
# include "stdio.h"
# define M 3
void main ( )
{
float MAT[M][2*M];
float MAT1[M][M];
float t;
int i,j,k,l;
/***********************************************/
www.eeworm.com/read/243633/12930540
c 简单逆阵.c
# include "stdio.h"
# define M 3
void main ( )
{
float MAT[M][2*M];
float MAT1[M][M];
float t;
int i,j,k,l;
/***********************************************/