代码搜索:线性分析
找到约 10,000 项符合「线性分析」的源代码
代码结果 10,000
www.eeworm.com/read/490428/6456348
m new_psk_performance.m
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%bpsk和Qpsk调制信号在高斯信道下的性能分析%
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
www.eeworm.com/read/182172/9213614
cpp ex_1.cpp
//求解线性方程组,采用三种方法:Guass消去法、Guass列主元素消去法
// 和直接三角形分解法(Boolittle方法 \ Crout方法)
// 针对课后第五题作个误差分析
#include"stdio.h"
#include"stdlib.h"
#include"math.h"
//求系数矩阵行列式
void det_A(float *A,int n)
{
www.eeworm.com/read/399063/7897311
txt e8.14.txt
!--------------------------------
!EX8.14 缺陷拱的几何非线性分析
finish
/clear
/filname,ex814
/prep7
r0=100
e=1e7
a=0.32
i0=1
h0=40
l0=160
et,1,beam3
mp,ex,1,e
r,1,a,i0,0.5
k,1,-l0/2
k,2,0,h0
k,
www.eeworm.com/read/399063/7897698
txt e8.08.txt
!EX8.8 中心受压铰接柱的几何非线性分析
finish
/clear
/filname,colu
/prep7
aa=100.0
ai=10000/12.0
l0=1000
em=2e5
pcr=acos(-1)*acos(-1)*em*ai/l0/l0
et,1,beam3
mp,ex,1,em
mp,prxy,1,0
r,1,aa,ai,10
k,1,0
k
www.eeworm.com/read/399063/7897846
txt e5.07.txt
!EX5.7 圆弧无铰拱几何非线性分析
finish
/clear
/prep7
et,1,beam3
mp,ex,1,2.0e5
mp,prxy,1,0.3
r,1,300,8000,20
csys,1
k,1,2000,60
k,2,2000,90
k,3,2000,120
l,1,2
l,2,3
csys,0
lesize,all,,,20
lmesh,all
www.eeworm.com/read/397861/8017830
txt e8.14.txt
!--------------------------------
!EX8.14 缺陷拱的几何非线性分析
finish
/clear
/filname,ex814
/prep7
r0=100
e=1e7
a=0.32
i0=1
h0=40
l0=160
et,1,beam3
mp,ex,1,e
r,1,a,i0,0.5
k,1,-l0/2
k,2,0,h0
k,
www.eeworm.com/read/397861/8018178
txt e8.08.txt
!EX8.8 中心受压铰接柱的几何非线性分析
finish
/clear
/filname,colu
/prep7
aa=100.0
ai=10000/12.0
l0=1000
em=2e5
pcr=acos(-1)*acos(-1)*em*ai/l0/l0
et,1,beam3
mp,ex,1,em
mp,prxy,1,0
r,1,aa,ai,10
k,1,0
k
www.eeworm.com/read/397861/8018318
txt e5.07.txt
!EX5.7 圆弧无铰拱几何非线性分析
finish
/clear
/prep7
et,1,beam3
mp,ex,1,2.0e5
mp,prxy,1,0.3
r,1,300,8000,20
csys,1
k,1,2000,60
k,2,2000,90
k,3,2000,120
l,1,2
l,2,3
csys,0
lesize,all,,,20
lmesh,all
www.eeworm.com/read/143496/12870927
m volterra_main_luzhenbo.m
% 混沌时间序列的 Volterra 自适应预测(一步预测) -- 主函数
% 参考文献:朱昀.水声信号非线性分析方法研究.西北工业大学博士学位论文.2002.06
% P28-38
clc
clear
close all
% dx/dt = sigma*(y(t)-x(t))
% dy/dt = r*x(t) - y(t) - x(t)*z(t)
% dz/dt = -b*z(t) + x(
www.eeworm.com/read/494312/6382121
m project_2.m
%项目二 连续系统的频域分析
%线性系统为;H(jw)=1/(jw+1);输入信号为周期矩形波
%画双边幅度频谱
tau_T = 1/4; %占空比
n = -20:20;
t = -3:0.01:3;
A = 2;
T = 2;
f_t = A*0.5*(square(pi*t,25)+1); %占空比为25%的方波
F_n = tau_T*sinc(tau_T*n*pi