代码搜索：磁场分布
找到约 3,825 项符合「磁场分布」的源代码
代码结果 3,825
www.eeworm.com/read/454747/7384047
m gyhf_cd_dmap4.m
%由改进方法得到的点方向图求连续分布方向图
clear;close all;
fp=imread('102_3.tif'); %读入指纹图象
imshow(fp);title('原始指纹图象') %显示指纹图象
M0=80;
Var0=200;
[len,wid]=size(fp);
fpn=zeros(len,wid); %为规格化后
www.eeworm.com/read/443020/7639345
m weibuerpu.m
function y=weibuerpu(a,b,n)
%由数据量为n的高斯白噪声产生向量为n，功率谱为高斯型的韦布尔分布的随机向量
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%
[z1,z2]=gaussian(n);
z1=5*z1;
z2=5*z2;
y1=sqrt(b^a/2)*z
www.eeworm.com/read/443020/7639356
m junyun.m
function y=junyun(n)
%0-1的均匀分布，n代表数据量，一般要大于1024
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
y=ones(1,n);
x=ones(1,n);
m=100000;
x0=mod(ceil(m*rand(1,1)),m);
x0=floor(x0/2);
x0=2*x0+1;
u=11;
www.eeworm.com/read/443020/7639373
m gaussian.m
function [y1,y2]=gaussian(n)
%产生数据量为n的两个相互独立高斯分布y1、y2
%---------------------------------------
%
k=1;
y1=zeros(1,n);
y2=zeros(1,n);
while(k
www.eeworm.com/read/299682/7839477
m weibuerpu.m
function y=weibuerpu(a,b,n)
%由数据量为n的高斯白噪声产生向量为n，功率谱为高斯型的韦布尔分布的随机向量
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%
[z1,z2]=gaussian(n);
z1=5*z1;
z2=5*z2;
y1=sqrt(b^a/2)*z
www.eeworm.com/read/299682/7839495
m junyun.m
function y=junyun(n)
%0-1的均匀分布，n代表数据量，一般要大于1024
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
y=ones(1,n);
x=ones(1,n);
m=100000;
x0=mod(ceil(m*rand(1,1)),m);
x0=floor(x0/2);
x0=2*x0+1;
u=11;
www.eeworm.com/read/299682/7839535
m gaussian.m
function [y1,y2]=gaussian(n)
%产生数据量为n的两个相互独立高斯分布y1、y2
%---------------------------------------
%
k=1;
y1=zeros(1,n);
y2=zeros(1,n);
while(k
www.eeworm.com/read/142732/12929374
htm oracle基本操作-4.htm
ORACLE的分布式管理
物理上存放于网络的多个ORACLE数据库，逻辑上可以看成一个单个的大数据库。用户可以通过网络对异地数据库中的
www.eeworm.com/read/141621/12994100
m example2_6.m
%输入矢量分布在一个二维输入空间，其变化范围分别为[0 2]和[0 1]，组织特征映射网络维数为[3 5]，
%用plotsom( )函数绘制组织特征映射。
P=[rand(1,400)*2;rand(1,400)];
net=newsom([0 2;0 1],[3 5]);
Plotsom(net.layers{1}.positions)
www.eeworm.com/read/319930/13439359
asv untitled2.asv
n=randn(1,100);%高斯白噪声
x=rand(1,100)%[-1,1]上均匀分布
for i=1:100
if (x(i)>0.5) (x(i)==0.5)
x(i)=1;
elseif x(i)0.5)