代码搜索:矩阵分析

找到约 10,000 项符合「矩阵分析」的源代码

代码结果 10,000
www.eeworm.com/read/243633/12930548

c 逆矩阵.c

#define N 5 /*[注]:修改6为你所要的矩阵阶数*/ #include "stdio.h" #include "conio.h" /*js()函数用于计算行列式,通过递归算法实现*/ int js(s,n) int s[][N],n; {int z,j,k,r,total=0; int b[N][N];/*b[N][N]用于存放,在矩阵s[
www.eeworm.com/read/243633/12930648

c 乘法矩阵.c

#include void main() { int i,j; int big[8][8]; for (i = 0;i < 8;i++) /*循环嵌套*/ for (j = 0;j < 8;j++) big[i][j] = i * j; /* 乘法表 */ big[2][6] = 748;
www.eeworm.com/read/243633/12930877

c 矩阵转换.c

void trans(int *p,int n) { int i,j,temp; int *pi,*pj; for(i=0;i
www.eeworm.com/read/243560/12933914

c 逆矩阵.c

#define N 5 /*[注]:修改6为你所要的矩阵阶数*/ #include "stdio.h" #include "conio.h" /*js()函数用于计算行列式,通过递归算法实现*/ int js(s,n) int s[][N],n; {int z,j,k,r,total=0; int b[N][N];/*b[N][N]用于存放,在矩阵s[
www.eeworm.com/read/243560/12933977

c 乘法矩阵.c

#include void main() { int i,j; int big[8][8]; for (i = 0;i < 8;i++) /*循环嵌套*/ for (j = 0;j < 8;j++) big[i][j] = i * j; /* 乘法表 */ big[2][6] = 748;
www.eeworm.com/read/243560/12934216

c 矩阵转换.c

void trans(int *p,int n) { int i,j,temp; int *pi,*pj; for(i=0;i
www.eeworm.com/read/329680/12938943

c 逆矩阵.c

#define N 5 /*[注]:修改6为你所要的矩阵阶数*/ #include "stdio.h" #include "conio.h" /*js()函数用于计算行列式,通过递归算法实现*/ int js(s,n) int s[][N],n; {int z,j,k,r,total=0; int b[N][N];/*b[N][N]用于存放,在矩阵s[
www.eeworm.com/read/329680/12939030

c 乘法矩阵.c

#include void main() { int i,j; int big[8][8]; for (i = 0;i < 8;i++) /*循环嵌套*/ for (j = 0;j < 8;j++) big[i][j] = i * j; /* 乘法表 */ big[2][6] = 748;
www.eeworm.com/read/329680/12939262

c 矩阵转换.c

void trans(int *p,int n) { int i,j,temp; int *pi,*pj; for(i=0;i
www.eeworm.com/read/242662/12994336

txt 矩阵相乘.txt

两个矩阵相乘的源程序 /*****************A=B*C******************/ #include #include #define X 3 #define Y 3 int a[X][Y]; int b[X][Y]; int c[X][Y]; void matrix(int b[][X],int c[][Y