代码搜索:矩阵分析
找到约 10,000 项符合「矩阵分析」的源代码
代码结果 10,000
www.eeworm.com/read/243633/12930548
c 逆矩阵.c
#define N 5 /*[注]:修改6为你所要的矩阵阶数*/
#include "stdio.h"
#include "conio.h"
/*js()函数用于计算行列式,通过递归算法实现*/
int js(s,n)
int s[][N],n;
{int z,j,k,r,total=0;
int b[N][N];/*b[N][N]用于存放,在矩阵s[
www.eeworm.com/read/243633/12930648
c 乘法矩阵.c
#include
void main()
{
int i,j;
int big[8][8];
for (i = 0;i < 8;i++) /*循环嵌套*/
for (j = 0;j < 8;j++)
big[i][j] = i * j; /* 乘法表 */
big[2][6] = 748;
www.eeworm.com/read/243633/12930877
c 矩阵转换.c
void trans(int *p,int n)
{
int i,j,temp;
int *pi,*pj;
for(i=0;i
www.eeworm.com/read/243560/12933914
c 逆矩阵.c
#define N 5 /*[注]:修改6为你所要的矩阵阶数*/
#include "stdio.h"
#include "conio.h"
/*js()函数用于计算行列式,通过递归算法实现*/
int js(s,n)
int s[][N],n;
{int z,j,k,r,total=0;
int b[N][N];/*b[N][N]用于存放,在矩阵s[
www.eeworm.com/read/243560/12933977
c 乘法矩阵.c
#include
void main()
{
int i,j;
int big[8][8];
for (i = 0;i < 8;i++) /*循环嵌套*/
for (j = 0;j < 8;j++)
big[i][j] = i * j; /* 乘法表 */
big[2][6] = 748;
www.eeworm.com/read/243560/12934216
c 矩阵转换.c
void trans(int *p,int n)
{
int i,j,temp;
int *pi,*pj;
for(i=0;i
www.eeworm.com/read/329680/12938943
c 逆矩阵.c
#define N 5 /*[注]:修改6为你所要的矩阵阶数*/
#include "stdio.h"
#include "conio.h"
/*js()函数用于计算行列式,通过递归算法实现*/
int js(s,n)
int s[][N],n;
{int z,j,k,r,total=0;
int b[N][N];/*b[N][N]用于存放,在矩阵s[
www.eeworm.com/read/329680/12939030
c 乘法矩阵.c
#include
void main()
{
int i,j;
int big[8][8];
for (i = 0;i < 8;i++) /*循环嵌套*/
for (j = 0;j < 8;j++)
big[i][j] = i * j; /* 乘法表 */
big[2][6] = 748;
www.eeworm.com/read/329680/12939262
c 矩阵转换.c
void trans(int *p,int n)
{
int i,j,temp;
int *pi,*pj;
for(i=0;i
www.eeworm.com/read/242662/12994336
txt 矩阵相乘.txt
两个矩阵相乘的源程序
/*****************A=B*C******************/
#include
#include
#define X 3
#define Y 3
int a[X][Y];
int b[X][Y];
int c[X][Y];
void matrix(int b[][X],int c[][Y