代码搜索:矩阵分析

找到约 10,000 项符合「矩阵分析」的源代码

代码结果 10,000
www.eeworm.com/read/450507/7482928

c 逆矩阵.c

#define N 5 /*[注]:修改6为你所要的矩阵阶数*/ #include "stdio.h" #include "conio.h" /*js()函数用于计算行列式,通过递归算法实现*/ int js(s,n) int s[][N],n; {int z,j,k,r,total=0; int b[N][N];/*b[N][N]用于存放,在矩阵s[
www.eeworm.com/read/449694/7497938

c 逆矩阵.c

#define N 5 /*[注]:修改6为你所要的矩阵阶数*/ #include "stdio.h" #include "conio.h" /*js()函数用于计算行列式,通过递归算法实现*/ int js(s,n) int s[][N],n; {int z,j,k,r,total=0; int b[N][N];/*b[N][N]用于存放,在矩阵s[
www.eeworm.com/read/449694/7497969

c 乘法矩阵.c

#include void main() { int i,j; int big[8][8]; for (i = 0;i < 8;i++) /*循环嵌套*/ for (j = 0;j < 8;j++) big[i][j] = i * j; /* 乘法表 */ big[2][6] = 748;
www.eeworm.com/read/449694/7498070

c 矩阵转换.c

void trans(int *p,int n) { int i,j,temp; int *pi,*pj; for(i=0;i
www.eeworm.com/read/434503/7862975

c 稀疏矩阵.c

#include #include #define MAX 10; typedef struct { int i,j; int e; }Triple1; typedef struct { Triple1 data[11];//data[0]未用 int rpos[11]; int mu,nu,tu; }TSMat
www.eeworm.com/read/298817/7933211

c 逆矩阵.c

#define N 5 /*[注]:修改6为你所要的矩阵阶数*/ #include "stdio.h" #include "conio.h" /*js()函数用于计算行列式,通过递归算法实现*/ int js(s,n) int s[][N],n; {int z,j,k,r,total=0; int b[N][N];/*b[N][N]用于存放,在矩阵s[
www.eeworm.com/read/298817/7933243

c 乘法矩阵.c

#include void main() { int i,j; int big[8][8]; for (i = 0;i < 8;i++) /*循环嵌套*/ for (j = 0;j < 8;j++) big[i][j] = i * j; /* 乘法表 */ big[2][6] = 748;
www.eeworm.com/read/298817/7933432

c 矩阵转换.c

void trans(int *p,int n) { int i,j,temp; int *pi,*pj; for(i=0;i
www.eeworm.com/read/396511/8102234

txt 矩阵算法.txt

#define maxsize 1000 #define ERROR 0 #define maxrc 100 #include #include #include typedef struct { int i,j; int v; }node,*pnode; typedef struct { int mu,nu,tu;
www.eeworm.com/read/195741/8133035

bak 生成矩阵.bak

dime a(5,5) for i=1 to 5 for j=1 to 5 do case case i