代码搜索：监听程序
找到约 10,000 项符合「监听程序」的源代码
代码结果 10,000
www.eeworm.com/read/129383/14248261
跑马程序
DLED：MOV R0，#0
WE：MOV A，#01
NEXT：MOV B，A
MOV P1，A
MOV DPTR，#TAB0
MOV A，R0
MOV C A，·A+DPTR
MOV P2，A
MOV R3，#0
LOP：MOV R4，
www.eeworm.com/read/127418/14356017
doc 程序.doc
www.eeworm.com/read/225832/14513925
c 程序.c
#include
unsigned char i,j,t,m,DelayTime,DispBuf[3];
//单片机脉搏测量仪源程序
//作者:吴汉清 ntwhq@tom.com
unsigned int n,mb;
unsigned char code
BitTab[3]={0xf7,0xef,0xdf};//位驱动码
unsigned char code
D
www.eeworm.com/read/225832/14513928
c 程序.c
#include
unsigned char i,j,t,m,DelayTime,DispBuf[3];
//单片机脉搏测量仪源程序
//作者:吴汉清 ntwhq@tom.com
unsigned int n,mb;
unsigned char code
BitTab[3]={0xf7,0xef,0xdf};//位驱动码
unsigned char code
D
www.eeworm.com/read/219690/14870054
txt 程序.txt
library ieee;
use ieee.std_logic_1164.all;
use ieee.std_logic_unsigned.all;
entity szz is
port(clk:in std_logic;
clk1:in std_logic;
md1:in std_logic;
md2:in std_logic_vector
www.eeworm.com/read/117716/14907593
txt 程序.txt
1. 递归方法
int C(int i, int j)
{ //返回c(i,j) 且计算k(i,j) = kay[i][j]
if (i==j) return 0; //一个矩阵的情形
if (i == j-1)
{ //两个矩阵的情形
kay[i][i+1]=i;
return r[i]*r[i+1]*r[i+2];
}
//多于两个矩阵的情形
//设u为
www.eeworm.com/read/213987/15118807
txt 程序.txt
#include
#include
#define uchar unsigned char
#define uint unsigned int
#define C8155 XBYTE[0x7000]
#define PA XBYTE[0x7001]
#define PB XBYTE[0x7002]
#define PC XBYTE[0x700
www.eeworm.com/read/213984/15118813
txt 程序.txt
#include
#include
#define uchar unsigned char
#define uint unsigned int
//============================
#define C8155 XBYTE[0x7000]
#define PA XBYTE[0x7001]
#define PB XBYTE
www.eeworm.com/read/212886/15146078