代码搜索:混沌理论
找到约 2,573 项符合「混沌理论」的源代码
代码结果 2,573
www.eeworm.com/read/408213/11401571
m examp3_29.m
x=[0:0.01:3*pi/2, 3*pi/2]; % 这样赋值能确保 $3\pi/2$ 点被包含在内
y=cos(15*x); plot(x,y)
syms x, A=int(cos(15*x),0,3*pi/2) % 求取理论值
h0=[0.1,0.01,0.001,0.0001,0.00001,0.000001]; v=[];
for h=h0,
x=[
www.eeworm.com/read/258265/11874155
cpp line.cpp
#include "stdafx.h"
#include
#include
using namespace std;
/*
mousePoint 为鼠标点击的点的数组
linePoint 为计算后拟合曲线上的点,只要以这些点来画线就可以绘制出曲线
controlPoint 为计算后得到的理论控制点数组
*/
void B3Li
www.eeworm.com/read/154929/11918414
m ysgserr.m
echo on
clear all
close all
snr_in_DB=-6:2:10;
for i=1:length(snr_in_DB),
[c1_e_r(i),c2_e_r(i)]=ysgspe(snr_in_DB(i));
end;
semilogy(snr_in_DB,c1_e_r,snr_in_DB,c2_e_r,'g*');
legend('理论误码率',
www.eeworm.com/read/341680/12073236
m examp3_29.m
x=[0:0.01:3*pi/2, 3*pi/2]; % 这样赋值能确保 $3\pi/2$ 点被包含在内
y=cos(15*x); plot(x,y)
syms x, A=int(cos(15*x),0,3*pi/2) % 求取理论值
h0=[0.1,0.01,0.001,0.0001,0.00001,0.000001]; v=[];
for h=h0,
x=[
www.eeworm.com/read/151608/12188639
m exm0641_1.m
%exm0641_1.m
%(1)求Fourier变换
syms t w;
ut=sym('Heaviside(t)'); %定义0时刻起跳的单位阶跃函数
UT=fourier(ut) %实施Fourier变换,给出与理论一致的结果
UTC=maple('convert',UT,'piecewise','w') %计算结果起指示作用
U
www.eeworm.com/read/337166/12386830
m exm0641_1.m
%exm0641_1.m
%(1)求Fourier变换
syms t w;
ut=sym('Heaviside(t)'); %定义0时刻起跳的单位阶跃函数
UT=fourier(ut) %实施Fourier变换,给出与理论一致的结果
UTC=maple('convert',UT,'piecewise','w') %计算结果起指示作用
U
www.eeworm.com/read/250122/12430651
m exm0641_1.m
%exm0641_1.m
%(1)求Fourier变换
syms t w;
ut=sym('Heaviside(t)'); %定义0时刻起跳的单位阶跃函数
UT=fourier(ut) %实施Fourier变换,给出与理论一致的结果
UTC=maple('convert',UT,'piecewise','w') %计算结果起指示作用
U
www.eeworm.com/read/132208/14105126
txt 算法说明.txt
在Visual C++6.0 WinXp下编译通过
采用类来实现
数据运算的结果保存在CString类中
理论上可对任意长的数据进行相加
在Release目录下有可执行文件,将*.txt拖放到longadd.exe上即可,*.txt为数据文件。
www.eeworm.com/read/131413/14147350
txt 自定义过程与函数 .txt
自定义过程与函数
--------------------------------------------------------------------------------
作者:不详 来源于:不详 发布时间:2005-2-13 15:48:00
Pascal 过程与函数
Pascal中的例程有两种形式:过程和函数。理论上说,过程是你要求计算机执行的操作,函数是能返回值的计
www.eeworm.com/read/232055/14209793
m examp3_29.m
x=[0:0.01:3*pi/2, 3*pi/2]; % 这样赋值能确保 $3\pi/2$ 点被包含在内
y=cos(15*x); plot(x,y)
syms x, A=int(cos(15*x),0,3*pi/2) % 求取理论值
h0=[0.1,0.01,0.001,0.0001,0.00001,0.000001]; v=[];
for h=h0,
x=[