代码搜索:概率分析
找到约 10,000 项符合「概率分析」的源代码
代码结果 10,000
www.eeworm.com/read/367675/2840109
m example5_4.m
function[newPop] = Select(oldPop,options)
q=options(2); % 选择最优的概率
e = size(oldPop,2);
n = size(oldPop,1); % 种群中个体的数目
newPop = zeros(n,e); % 初始化
fit = zeros(n,1); % 初始化
x=z
www.eeworm.com/read/359763/2972326
m example5_36.m
function NewChrom = mut(OldChrom,Pm,BaseV)
% OldChrom-当代种群的染色体
% Pm-变异概率
% BaseV-染色体基
[Nind, Lind] = size(OldChrom) ;
if nargin < 2, Pm = 0.7/Lind ; end
if isnan(Pm), Pm = 0.7/Lind; end
if (n
www.eeworm.com/read/359763/2972348
m example5_4.m
function[newPop] = Select(oldPop,options)
q=options(2); % 选择最优的概率
e = size(oldPop,2);
n = size(oldPop,1); % 种群中个体的数目
newPop = zeros(n,e); % 初始化
fit = zeros(n,1); % 初始化
x=z
www.eeworm.com/read/394253/8240441
m entropy.m
function h=entropy(p)
%H=ENTROPY(P)返回概率矢
%量P的熵函数。
if length (find (p10e-10,
error ('Not a prob.vector,comp
www.eeworm.com/read/393857/8258530
m c69.m
function NewChrom = mut(OldChrom,Pm,BaseV)
% OldChrom-当代种群的染色体
% Pm-变异概率
% BaseV-染色体基
[Nind, Lind] = size(OldChrom) ;
if nargin < 2, Pm = 0.7/Lind ; end
if isnan(Pm), Pm = 0.7/Lind; end
if (n
www.eeworm.com/read/393857/8258707
m d1.m
function[newPop] = Select(oldPop,options)
q=options(2); % 选择最优的概率
e = size(oldPop,2);
n = size(oldPop,1); % 种群中个体的数目
newPop = zeros(n,e); % 初始化
fit = zeros(n,1); % 初始化
x=z
www.eeworm.com/read/267744/11165232
m example5_36.m
function NewChrom = mut(OldChrom,Pm,BaseV)
% OldChrom-当代种群的染色体
% Pm-变异概率
% BaseV-染色体基
[Nind, Lind] = size(OldChrom) ;
if nargin < 2, Pm = 0.7/Lind ; end
if isnan(Pm), Pm = 0.7/Lind; end
if (n
www.eeworm.com/read/267744/11165270
m example5_4.m
function[newPop] = Select(oldPop,options)
q=options(2); % 选择最优的概率
e = size(oldPop,2);
n = size(oldPop,1); % 种群中个体的数目
newPop = zeros(n,e); % 初始化
fit = zeros(n,1); % 初始化
x=z
www.eeworm.com/read/249743/12476996
m example5_36.m
function NewChrom = mut(OldChrom,Pm,BaseV)
% OldChrom-当代种群的染色体
% Pm-变异概率
% BaseV-染色体基
[Nind, Lind] = size(OldChrom) ;
if nargin < 2, Pm = 0.7/Lind ; end
if isnan(Pm), Pm = 0.7/Lind; end
if (n
www.eeworm.com/read/249743/12477049
m example5_4.m
function[newPop] = Select(oldPop,options)
q=options(2); % 选择最优的概率
e = size(oldPop,2);
n = size(oldPop,1); % 种群中个体的数目
newPop = zeros(n,e); % 初始化
fit = zeros(n,1); % 初始化
x=z