代码搜索:概率分析

找到约 10,000 项符合「概率分析」的源代码

代码结果 10,000
www.eeworm.com/read/367675/2840109

m example5_4.m

function[newPop] = Select(oldPop,options) q=options(2); % 选择最优的概率 e = size(oldPop,2); n = size(oldPop,1); % 种群中个体的数目 newPop = zeros(n,e); % 初始化 fit = zeros(n,1); % 初始化 x=z
www.eeworm.com/read/359763/2972326

m example5_36.m

function NewChrom = mut(OldChrom,Pm,BaseV) % OldChrom-当代种群的染色体 % Pm-变异概率 % BaseV-染色体基 [Nind, Lind] = size(OldChrom) ; if nargin < 2, Pm = 0.7/Lind ; end if isnan(Pm), Pm = 0.7/Lind; end if (n
www.eeworm.com/read/359763/2972348

m example5_4.m

function[newPop] = Select(oldPop,options) q=options(2); % 选择最优的概率 e = size(oldPop,2); n = size(oldPop,1); % 种群中个体的数目 newPop = zeros(n,e); % 初始化 fit = zeros(n,1); % 初始化 x=z
www.eeworm.com/read/394253/8240441

m entropy.m

function h=entropy(p) %H=ENTROPY(P)返回概率矢 %量P的熵函数。 if length (find (p10e-10, error ('Not a prob.vector,comp
www.eeworm.com/read/393857/8258530

m c69.m

function NewChrom = mut(OldChrom,Pm,BaseV) % OldChrom-当代种群的染色体 % Pm-变异概率 % BaseV-染色体基 [Nind, Lind] = size(OldChrom) ; if nargin < 2, Pm = 0.7/Lind ; end if isnan(Pm), Pm = 0.7/Lind; end if (n
www.eeworm.com/read/393857/8258707

m d1.m

function[newPop] = Select(oldPop,options) q=options(2); % 选择最优的概率 e = size(oldPop,2); n = size(oldPop,1); % 种群中个体的数目 newPop = zeros(n,e); % 初始化 fit = zeros(n,1); % 初始化 x=z
www.eeworm.com/read/267744/11165232

m example5_36.m

function NewChrom = mut(OldChrom,Pm,BaseV) % OldChrom-当代种群的染色体 % Pm-变异概率 % BaseV-染色体基 [Nind, Lind] = size(OldChrom) ; if nargin < 2, Pm = 0.7/Lind ; end if isnan(Pm), Pm = 0.7/Lind; end if (n
www.eeworm.com/read/267744/11165270

m example5_4.m

function[newPop] = Select(oldPop,options) q=options(2); % 选择最优的概率 e = size(oldPop,2); n = size(oldPop,1); % 种群中个体的数目 newPop = zeros(n,e); % 初始化 fit = zeros(n,1); % 初始化 x=z
www.eeworm.com/read/249743/12476996

m example5_36.m

function NewChrom = mut(OldChrom,Pm,BaseV) % OldChrom-当代种群的染色体 % Pm-变异概率 % BaseV-染色体基 [Nind, Lind] = size(OldChrom) ; if nargin < 2, Pm = 0.7/Lind ; end if isnan(Pm), Pm = 0.7/Lind; end if (n
www.eeworm.com/read/249743/12477049

m example5_4.m

function[newPop] = Select(oldPop,options) q=options(2); % 选择最优的概率 e = size(oldPop,2); n = size(oldPop,1); % 种群中个体的数目 newPop = zeros(n,e); % 初始化 fit = zeros(n,1); % 初始化 x=z