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www.eeworm.com/read/465794/7046132

m crossover.m

%交叉 crossover %pc:交叉概率 %pp:群体交叉比例 function pop=crossover(pop,pp,pc,nStrLen) nc=round(size(pop,1)*pp/2); for i=1:nc one=round(rand*(size(pop,1)-1)+1); two=round(rand*(size(pop,1)-1))+
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www.eeworm.com/read/304790/7114567

m crossover.m

function popnew=crossover(pop,pcro,n,length) %交叉函数 %pcro为交叉概率 k=1; i=0; while (k
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www.eeworm.com/read/464287/7166571

m c69.m

function NewChrom = mut(OldChrom,Pm,BaseV) % OldChrom-当代种群的染色体 % Pm-变异概率 % BaseV-染色体基 [Nind, Lind] = size(OldChrom) ; if nargin < 2, Pm = 0.7/Lind ; end if isnan(Pm), Pm = 0.7/Lind; end if (n
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www.eeworm.com/read/464287/7166651

m d1.m

function[newPop] = Select(oldPop,options) q=options(2); % 选择最优的概率 e = size(oldPop,2); n = size(oldPop,1); % 种群中个体的数目 newPop = zeros(n,e); % 初始化 fit = zeros(n,1); % 初始化 x=z
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www.eeworm.com/read/460021/7258663

m example5_36.m

function NewChrom = mut(OldChrom,Pm,BaseV) % OldChrom-当代种群的染色体 % Pm-变异概率 % BaseV-染色体基 [Nind, Lind] = size(OldChrom) ; if nargin < 2, Pm = 0.7/Lind ; end if isnan(Pm), Pm = 0.7/Lind; end if (n
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www.eeworm.com/read/460021/7258685

m example5_4.m

function[newPop] = Select(oldPop,options) q=options(2); % 选择最优的概率 e = size(oldPop,2); n = size(oldPop,1); % 种群中个体的数目 newPop = zeros(n,e); % 初始化 fit = zeros(n,1); % 初始化 x=z
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www.eeworm.com/read/457431/7325558

m cross.m

function [cpop ,len,v]=cross(child,bounds,CP) %交叉函数，采取点交叉 %[newpop ,len]=cross(child,bounds,CP) %child 复制后的种群 %bounds 边界约束 %CP 交叉概率 %newpop 交叉后的新种群 %len 每个变量
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www.eeworm.com/read/457186/7333096

m crossover.m

function popnew=crossover(pop,pcro,n,length) %交叉函数 %pcro为交叉概率 k=1; i=0; while (k
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www.eeworm.com/read/398093/8005362

doc suanfa.doc

其中★高概率考点词▲为重点考点词●●其他考点词 ×为永赔词汇 ※※※※※※※※※※※※※※※※※※※※※※※※※※※※※ 97.1 41.AS a ______ actor,he can perform,sing,dance and play several kinds of musical instruments. A.flexible 灵活的，柔韧的 n.flexibility ★B
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www.eeworm.com/read/297044/8057653

m mutation.m

function popnew=mutation(pop,pmut,popsize,ncity) %变异函数 %pmut为变异概率 k=1; while k
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