代码搜索:查表法
找到约 10,000 项符合「查表法」的源代码
代码结果 10,000
www.eeworm.com/read/130875/5950123
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Attribute VB_Name = "modMethod"
'两组判别
Option Explicit
'全主元高斯-约当消去法求逆矩阵
'A(1 To m, 1 To m):开始存放欲求逆的矩阵,最终存求逆的结果矩阵,m是自变量个数
Public Sub Invert(a() As Double)
Dim n As Integer, ep As Double
D
www.eeworm.com/read/119338/6090767
java ex_4_2_4.java
/*
*文件名:ex_4_2_4.java
*说 明:一维数组应用举例
* 冒泡法排序
*/
public class ex_4_2_4
{
public static void main(String args[])
{
int i,j;
//定义并初始化数组
int intArray[]={30,1,-9,70,25,30,50,80,100
www.eeworm.com/read/222514/6283160
txt jacobi-matlab.txt
Jacobi迭代法的Matlab程序
function [x]=Jacobi_iterative(A,b)
% 用Jacobi迭代求解线性方程组,矩阵A是方阵
x0=zeros(1,length(b)); % 赋初值
tol=10^(-6); % 给定误差界
N=100; % 给定最大迭代次数
[n,n]=size(A); % 确定矩阵A的阶
www.eeworm.com/read/286218/6298388
c fcm.c
//模糊聚类分析法
#include
#include
#include
int N;//样本数
int M;//特征数
double Q//置信水平
double **DATA//样本数据
double *P//平均值矩阵
double *P1//标准差矩阵
double **DATA2
double **
www.eeworm.com/read/358107/6324248
txt xylmat.txt
%%用匈牙利法解指派问题
%%C是效益矩阵
function [y,fval,flag]=Hungary(C)
[m,n]=size(C);
tempC=C;
%%%以下两个循环使每行每列都出现零元素
for i=1:m
tempC(i,:)=tempC(i,:)-min(tempC(i,:));
end
for i=1:n
tempC(:,i)=tempC
www.eeworm.com/read/494076/6387642
m pdes2ds_collocation.m
function PDEs2DS_Collocation
% 用对称正交配置法求解固定床反应器二维拟均相稳态模型(二维稳态PDE方程组)
% (只在r方向无因次化)
%
% Author: HUANG Huajiang
% Copyright 2003 UNILAB Research Center,
% East China University of Science a
www.eeworm.com/read/492513/6415093
c pinyin.c
#include
#include
struct PY_index
{
char *PY;
char *PY_mb;
};
//"拼音输入法汉字排列表,码表(mb)"
code char PY_mb_a[] ={"阿啊"};
code char PY_mb_ai[] ={"哎哀唉埃挨皑癌矮蔼艾爱隘碍"};
www.eeworm.com/read/484981/6569780
java sample3_6.java
public class Sample3_6
{
public static void main(String[] args)
{
//通过枚举法创建了数组对象,列举了12个元素值。
int[] d=new int[]{1,4,6,2,3,78,21,45,79,34,113,76};
//打印数组长度
System.out.println("d.len
www.eeworm.com/read/480785/6661586
m opt11.m
% 最优化作业 第十一章 模式搜索法
% 08203-5班 王永亮 2008200383
clc;
clear all;
delta = 1; alpha = 1; beta = 0.25; epsilon = 0.11;
k = 1; j = 1;
e1 = [1 0]'; e2 = [0 1]';
% x1 = [0 0]'; %(1)
beta = 0.5; x1 =
www.eeworm.com/read/480611/6666842
cpp 8.6.cpp
/*用炫截法球方程f(x)=x3-5x2+16x-80=0的根*/
#include
#include
//int main()
float f(float x)
{
float y;
y=((x-5.0)*x+16.0)*x-80.0;
return(y);
}
float xpoint (float x1,float