代码搜索:查表法

找到约 10,000 项符合「查表法」的源代码

代码结果 10,000
www.eeworm.com/read/410291/2214048

properties msgzk_zh_tw.properties

#"charset=utf-8" # # Errors # # #-=PAGE_NOT_FOUND 1000=找不到 {0}。 #-=PORTLET_PAGE_REQUIRED 1001=ZUML 網頁的位址必須指定於 zk_page 參數。 #-=PAGE_FAILED 1002={ 無法載入 {0}。 原因: {1} {2} } #-=UPDATE_OBSOLETE_PAGE 1010={
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cs sample5_9.cs

/* * 示例程序Sample5_9: NLEquations类的求非线性方程组一组实根的拟牛顿法 */ using System; using CSharpAlgorithm.Algorithm; namespace CSharpAlgorithm.Sample { class Class1 { // 建立NLEquation的子类,在其中重载函
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cs sample5_10.cs

/* * 示例程序Sample5_10: NLEquations类的求非线性方程组最小二乘解的广义逆法 */ using System; using CSharpAlgorithm.Algorithm; namespace CSharpAlgorithm.Sample { class Class1 { // 建立NLEquation的子类,在其中重
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txt 例4.9.txt

例4.9 用弦截法求方程f(x)=x3次方-5x2次方+16x-80=0的根。 #include #include #include using namespace std; double f(double); //函数声明 double xpoint(double, double);
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java camera.java

package myprojects.graph3dapp; import java.awt.*; class Camera { protected Vector3d vrp = new Vector3d(0, 0, 3); //观察参考点 protected Vector3d vpn = new Vector3d(0, 0, -1); //观察平面法向 protected
www.eeworm.com/read/354679/3075246

cpp 510.cpp

//5.10 LR分析法在词法分析器自动构造中的应用(分析表未最小化) #include #include #include #include //常数 const char *word[]={//单词表 "begin","end","integer","real","=","+","++
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cs sample5_9.cs

/* * 示例程序Sample5_9: NLEquations类的求非线性方程组一组实根的拟牛顿法 */ using System; using CSharpAlgorithm.Algorithm; namespace CSharpAlgorithm.Sample { class Class1 { // 建立NLEquation的子类,在其中重载函
www.eeworm.com/read/254498/4382012

cs sample5_10.cs

/* * 示例程序Sample5_10: NLEquations类的求非线性方程组最小二乘解的广义逆法 */ using System; using CSharpAlgorithm.Algorithm; namespace CSharpAlgorithm.Sample { class Class1 { // 建立NLEquation的子类,在其中重
www.eeworm.com/read/158018/5601544

java ex_3_3_15.java

/* *文件名 ex_3_3_15.java *说 明:do-while循环应用举例 * 牛顿迭代法求正数平方根 */ import java.io.*; class ex_3_3_15 { public static void main(String args[]) throws IOException { // 精确度要求 fina
www.eeworm.com/read/473390/6851896

m rjiance.m

function Rjiance() load string1.mat fs=sfreq; M=length(x); t=1:M; x=x'; for i=5:1000 dif(i)=2*(x(i)-x(i-4))+x(i-1)-x(i-3); %微分阈值法 dif=abs(dif); end; [ymax,p]=max(dif);