代码搜索：数字中频
找到约 10,000 项符合「数字中频」的源代码
代码结果 10,000
www.eeworm.com/read/252462/12281653
c display.c
#include
#include
#include "lcd.h"
void Bit_display(unsigned char X,unsigned char Y) //位显示函数，将对转换结果的数字量进行“0”或“1”的显示
{
if(Y)
LCD_write
www.eeworm.com/read/252193/12294697
c 7-44.c
/*将字符串a，b，c 分别采用10，2，16进制转换成数字*/
#include
main()
{
char a[]="1000000000";
char b[]="1000000000";
char c[]="ffff";
printf("a=%d\n",strtol(a,NULL,10));
printf("b=%d\n",strtol(b,NULL,2)
www.eeworm.com/read/252193/12294754
c 7-43.c
/*将字符串a，b，c 分别采用十，二，十六进制转换成数字*/
#include
main()
{
char a[]="1000000000";
char b[]="1000000000";
char c[]="ffff";
printf("a=%d\n",strtod(a,NULL));
printf("b=%d\n",strtod(b,NULL));
pr
www.eeworm.com/read/132201/14105548
h change.h
//change.h//
//数制转换函数集,将数字转换成ASCII字符串，结果保存到outbufful缓冲区
//#ifndef __CHANGE_H__
//#define __CHANGE_H__
#define UCHAR unsigned char
#define UINT unsigned int
#define ULONG unsigned long
#define L
www.eeworm.com/read/234020/14125609
h change.h
//change.h//
//数制转换函数集,将数字转换成ASCII字符串，结果保存到outbufful缓冲区
//#ifndef __CHANGE_H__
//#define __CHANGE_H__
#define UCHAR unsigned char
#define UINT unsigned int
#define ULONG unsigned long
#define L
www.eeworm.com/read/131409/14147399
cpp analyseword.cpp
/*
Author : Deimos
Date : 2005/4/13
Modify : 2005/4/14
Title : C语言简易词法分析器
Version: Demo
*/
/*
保留字：if、int、for、while、do、return、break、continue -- 编号：1
标识符：除保留字以外的字符串或字符（数字不行） --
www.eeworm.com/read/131093/14161189
cpp test2.cpp
#include
long factorial(int nummer); // 计排列组合嘅函数
void main()
{
int i,n,m;
cout m;
coutn;
double answer=m;
for(i=1;i
www.eeworm.com/read/233105/14169220
c re.c
#include
main()
{
int n,s,j,k,p;
int a[100];//最多允许100人
printf("请输入人数：");
scanf("%d",&n);
printf("请输入数字：");
scanf("%d",&s);
for(j=0;j
www.eeworm.com/read/228883/14358357
c yjkey.c
/*.....................键盘程序.................*/
#include
#include
unsigned char key,Byte1,Byte2,count=0;//键盘中数字对应的汉字库中的值
unsigned char i,j,pwbuf[6],pw[6];
bit pwflag,enterfla
www.eeworm.com/read/127013/14389953
c re.c
#include
main()
{
int n,s,j,k,p;
int a[100];//最多允许100人
printf("请输入人数：");
scanf("%d",&n);
printf("请输入数字：");
scanf("%d",&s);
for(j=0;j