代码搜索:微分几何
找到约 3,133 项符合「微分几何」的源代码
代码结果 3,133
www.eeworm.com/read/399063/7897493
txt e8.05.txt
!EX8.5 端部受集中力的悬臂梁几何非线性分析
finish
/clear
/prep7
ee=207e3
b=10
h=10
lcd=300
aa=b*h
iz=b*h*h*h/12
phz=ee*iz/lcd/lcd
et,1,beam3
mp,ex,1,ee
mp,prxy,1,0.3
r,1,aa,iz,h
k,1
k,2,lcd
l,1,2
lesi
www.eeworm.com/read/399063/7897504
txt e8.13.txt
!-------------------------------
!EX8.13 完善拱的几何非线性分析
!变形永远是正对称
finish
/clear
/prep7
r0=100
e=1e7
a=0.32
i0=1
h0=40
l0=160
et,1,beam3
mp,ex,1,e
r,1,a,i0,0.5
k,1,-l0/2
k,2,0,h0
k,3,l0/2
www.eeworm.com/read/399063/7897666
txt e9.09.txt
!ex9.9 工作台的瞬态动力分析-完全法
finish
/clear
/prep7
!定义几何参数
width=1
length=2
high=-1
!定义单元与材料性质等
et,1,shell63
et,2,beam4
mp,ex,1,2e11
mp,prxy,1,0.3
mp,dens,1,7800
r,1,0.02
r,2,2e-4,2e-8,2e-8,0.0
www.eeworm.com/read/399063/7897824
txt e2.01a.txt
!EX2.1A-整圈数圆柱形螺旋弹簧的几何建模
FINISH
/CLEAR
/PREP7
!1.定义弹簧参数
D=4
C=8
N=10
DZ=C*D
T=DZ/2.5
*IF,T,LT,D,THEN
T=D
*ENDIF
!2.创建一圈螺旋线
CSYS,1
K,1,DZ/2,0,-T/2
K,2,DZ/2,180
L,1,2
CSYS,0
LSYMM,Z,1
www.eeworm.com/read/397861/8017975
txt e8.05.txt
!EX8.5 端部受集中力的悬臂梁几何非线性分析
finish
/clear
/prep7
ee=207e3
b=10
h=10
lcd=300
aa=b*h
iz=b*h*h*h/12
phz=ee*iz/lcd/lcd
et,1,beam3
mp,ex,1,ee
mp,prxy,1,0.3
r,1,aa,iz,h
k,1
k,2,lcd
l,1,2
lesi
www.eeworm.com/read/397861/8017983
txt e8.13.txt
!-------------------------------
!EX8.13 完善拱的几何非线性分析
!变形永远是正对称
finish
/clear
/prep7
r0=100
e=1e7
a=0.32
i0=1
h0=40
l0=160
et,1,beam3
mp,ex,1,e
r,1,a,i0,0.5
k,1,-l0/2
k,2,0,h0
k,3,l0/2
www.eeworm.com/read/397861/8018139
txt e9.09.txt
!ex9.9 工作台的瞬态动力分析-完全法
finish
/clear
/prep7
!定义几何参数
width=1
length=2
high=-1
!定义单元与材料性质等
et,1,shell63
et,2,beam4
mp,ex,1,2e11
mp,prxy,1,0.3
mp,dens,1,7800
r,1,0.02
r,2,2e-4,2e-8,2e-8,0.0
www.eeworm.com/read/397861/8018294
txt e2.01a.txt
!EX2.1A-整圈数圆柱形螺旋弹簧的几何建模
FINISH
/CLEAR
/PREP7
!1.定义弹簧参数
D=4
C=8
N=10
DZ=C*D
T=DZ/2.5
*IF,T,LT,D,THEN
T=D
*ENDIF
!2.创建一圈螺旋线
CSYS,1
K,1,DZ/2,0,-T/2
K,2,DZ/2,180
L,1,2
CSYS,0
LSYMM,Z,1
www.eeworm.com/read/130817/14173602
m func7p3.m
%func7p3.m求解非线性方程
%(1)迭代公式,请见代码
%(2)/(3) x0=-(8000)^(1/2),求解。运用几何知识,可知在x(i)点的坐标为x(i)/2
x0=-(8000)^(1/2)+30;x00=-(8000)^(1/2);tol=0.001;x1=0;i=1
xx=linspace(x00,0,5)
while(x00
www.eeworm.com/read/122931/14656545
txt jbuilder 3 foundation 固 _linux疄免 费java开勑犯垃.txt
JBuilder3Foundation基于Linux的免费Java开发环境
曾几何时,Pascal和Windows应用编程铸就的辉煌已成为过眼云烟。如今,Inprise卷土重来,在经历磨难与洗礼之后推出了强大的Java开发工具JBuilder3,此番又推出了基于Linux的免费Java开发环境——JBuilder3Foundation。美国JavaWorld近日对该集成开发环境进行了测试。
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