代码搜索：弯针
找到约 468 项符合「弯针」的源代码
代码结果 468
www.eeworm.com/read/179301/9361464
c ysfh.c
#include
typedef struct LNode /*定义链表的存储结构*/
{
int num,pwd;
struct LNode *next;
};
struct LNode *head,*p,*pt;
/*head是头结点指针，p是当前指针的前一指针， pt是当前指针
www.eeworm.com/read/363342/9958090
c 汉诺塔2.c
move(char getone,char putone)
{
printf("%c-->%c\n",getone,putone);
}
void hanoi(int n,char one,char two,char three)
{
if(n==1)move(one,three);
else{
hanio(n-1,one,three,two); \*把A针的n-1个盘子通过
www.eeworm.com/read/276181/10758304
c 汉诺塔2.c
move(char getone,char putone)
{
printf("%c-->%c\n",getone,putone);
}
void hanoi(int n,char one,char two,char three)
{
if(n==1)move(one,three);
else{
hanio(n-1,one,three,two); \*把A针的n-1个盘子通过
www.eeworm.com/read/458027/7313814
c 汉诺塔2.c
move(char getone,char putone)
{
printf("%c-->%c\n",getone,putone);
}
void hanoi(int n,char one,char two,char three)
{
if(n==1)move(one,three);
else{
hanio(n-1,one,three,two); \*把A针的n-1个盘子通过
www.eeworm.com/read/450798/7476656
c 汉诺塔2.c
move(char getone,char putone)
{
printf("%c-->%c\n",getone,putone);
}
void hanoi(int n,char one,char two,char three)
{
if(n==1)move(one,three);
else{
hanio(n-1,one,three,two); \*把A针的n-1个盘子通过
www.eeworm.com/read/449694/7497943
c 汉诺塔2.c
move(char getone,char putone)
{
printf("%c-->%c\n",getone,putone);
}
void hanoi(int n,char one,char two,char three)
{
if(n==1)move(one,three);
else{
hanio(n-1,one,three,two); \*把A针的n-1个盘子通过
www.eeworm.com/read/298817/7933216
c 汉诺塔2.c
move(char getone,char putone)
{
printf("%c-->%c\n",getone,putone);
}
void hanoi(int n,char one,char two,char three)
{
if(n==1)move(one,three);
else{
hanio(n-1,one,three,two); \*把A针的n-1个盘子通过
www.eeworm.com/read/332124/12777190
c 汉诺塔2.c
move(char getone,char putone)
{
printf("%c-->%c\n",getone,putone);
}
void hanoi(int n,char one,char two,char three)
{
if(n==1)move(one,three);
else{
hanio(n-1,one,three,two); \*把A针的n-1个盘子通过
www.eeworm.com/read/243633/12930565
c 汉诺塔2.c
move(char getone,char putone)
{
printf("%c-->%c\n",getone,putone);
}
void hanoi(int n,char one,char two,char three)
{
if(n==1)move(one,three);
else{
hanio(n-1,one,three,two); \*把A针的n-1个盘子通过
www.eeworm.com/read/243560/12933921
c 汉诺塔2.c
move(char getone,char putone)
{
printf("%c-->%c\n",getone,putone);
}
void hanoi(int n,char one,char two,char three)
{
if(n==1)move(one,three);
else{
hanio(n-1,one,three,two); \*把A针的n-1个盘子通过