代码搜索：实例教学
找到约 10,000 项符合「实例教学」的源代码
代码结果 10,000
www.eeworm.com/read/289579/8541561
c 实例3.c
#include
#include
main(int argc, char *argv[])
{
FILE *in,*out;
char ch;
if(argc!=3);
{
printf("You forgot to enter a filename\n");
exit(0);
www.eeworm.com/read/289579/8541564
c 实例1.c
#include
#include
main()
{
FILE *fp;
char ch,filename[10];
scanf("%s",filename);
if( (fp=fopen(filename,"w") )==NULL)
{
printf("cannot open fil
www.eeworm.com/read/289579/8541572
c 实例2.c
#include
#include
main()
{
FILE *in,*out;
char ch,infile[10],outfile[10];
printf("Enter the infile nmae:\n");
scanf("%s",infile);
printf("Enter the o
www.eeworm.com/read/388214/8627495
doc 实例程序.doc
www.eeworm.com/read/287962/8656479
txt 单实例问题.txt
作者：rick1126
email: rickzhang@sina.com
日期：8/6/2001 9:55:10 PM
单实例问题目前主要就是一个是应用程序的不可重入, 另一个就是函数的不可重入.
1. 应用程序的不可重入
1) FindWindow
使用FindWindow( 类名, 标题 )可以保证那些使用主窗口的应用程序的单实例, 不过有时候因为标题用来表示某些动态信
www.eeworm.com/read/387130/8704054
doc 实例程序.doc
www.eeworm.com/read/429982/8775435
m 实例01.m
function shili01
h0=figure('toolbar','none',...
'position',[198 56 350 300],...
'name','实例01');
h1=axes('parent',h0,...
'visible','off');
x=-pi:0.05:pi;
y=sin(x);
plot(x,y);
xlabel
www.eeworm.com/read/385582/8798093
m 实例01.m
function shili01
h0=figure('toolbar','none',...
'position',[198 56 350 300],...
'name','实例01');
h1=axes('parent',h0,...
'visible','off');
x=-pi:0.05:pi;
y=sin(x);
plot(x,y);
xlabel