代码搜索：字符型
找到约 10,000 项符合「字符型」的源代码
代码结果 10,000
www.eeworm.com/read/329680/12939175
c 反出字符.c
/*由Andy自行修改为支持大小写转换*/
#include
main()
{
int i=0,n=0;
char ascs[]={"abcdefghijklmnopqrstuvwxyz"};
char ascb[]={"ABCDEFGHIJKLMNOPQRSTUVWXYZ"};
char a,b[20];
while ((a=get
www.eeworm.com/read/314101/13574809
exe 字符串.exe
www.eeworm.com/read/314101/13574811
txt 字符串.txt
datas segment
string db 20,?,20 dup(?)
input db 0ah,0dh,'Please input one string:$'
output1 db 0ah,0dh,' the number of others is:$'
output2 db 0ah,0dh,' the number of data
www.eeworm.com/read/314101/13574813
obj 字符串.obj
www.eeworm.com/read/314101/13574817
asm 字符串.asm
datas segment
string db 20,?,20 dup(?)
input db 0ah,0dh,'Please input one string:$'
output1 db 0ah,0dh,' The number of others is:$'
output2 db 0ah,0dh,' The number of data
www.eeworm.com/read/311771/13626526
c 记字符数.c
#include
#include
int upper=0,lower=0,diqit=0,space=0; /*注意，因为upper,space等并没有成为形参，它们只是局部变量，在不同的函数中互不干扰，所以不将其设为全局变量就不能起作用*/
void count(char str[])
{ int i;
char c;
for(i
www.eeworm.com/read/308157/13707179
c 反出字符.c
/*由Andy自行修改为支持大小写转换*/
#include
main()
{
int i=0,n=0;
char ascs[]={"abcdefghijklmnopqrstuvwxyz"};
char ascb[]={"ABCDEFGHIJKLMNOPQRSTUVWXYZ"};
char a,b[20];
while ((a=get
www.eeworm.com/read/151133/5685970
c 反出字符.c
/*由Andy自行修改为支持大小写转换*/
#include
main()
{
int i=0,n=0;
char ascs[]={"abcdefghijklmnopqrstuvwxyz"};
char ascb[]={"ABCDEFGHIJKLMNOPQRSTUVWXYZ"};
char a,b[20];
while ((a=get
www.eeworm.com/read/150780/6348262
m bam_字符.m
%仿真从噪声背景中进行联想过程
% BAM
clc
%网络初始化
%调用字母矩阵中的字符，ALPHABET - 35x26 matrix of 5x7 bit maps for each letter,TARGETS - 26x26 target vectors.
[alphabet,targets]=prprob;
B=1;% B为噪声干扰的强度,输入向量的标准差
%训练样本