代码搜索:协方差矩阵
找到约 10,000 项符合「协方差矩阵」的源代码
代码结果 10,000
www.eeworm.com/read/266227/11235955
m givens.m
function [c,s]=givens(A)
%Givens变换得到变换矩阵的参数
if A(2)==0
c=1;
s=0;
elseif abs(A(2))>=abs(A(1))
t=A(1)/A(2);
s=(1+t^2)^(-1/2);
c=s*t;
else
t=A(2)/A(1);
c=(1+t^2)^(-
www.eeworm.com/read/411023/11261072
cpp 后方交会.cpp
#include "stdio.h"
#include "math.h"
#include "iostream.h"
#define N 4
#define M 2*N
void Transpose(double a[M][6],double b[6][M]) //将矩阵a[]转置,存储在b[]中
{
int i,j;
for(i=0;i
www.eeworm.com/read/411011/11261189
cpp spaceresection.cpp
#include "stdio.h"
#include "math.h"
#include "iostream.h"
#define N 4
#define M 2*N
void Transpose(double a[M][6],double b[6][M]) //将矩阵a[]转置,存储在b[]中
{
int i,j;
for(i=0;i
www.eeworm.com/read/147421/12553645
m 嵌入.m
clear;
X=double(imread('lena.bmp'));
[XCsource,XSsource]=wavedec2(X,3,'db1');
W=double(imread('UESTC.bmp')); %'double'将矩阵的元素变成双精度元素
lowarray=reshape(XCsource(1:4096),64,64); %convert matrix XCso
www.eeworm.com/read/247679/12631805
c aja_mar.c
//程序实例8_1
//邻接矩阵的生成
#include
#include
#define Infinite 9999
#define Max 100
int A[Max][Max];
void adjm(int v[][2],int w[],int n,int e,int t)
{
int k,m=0;
www.eeworm.com/read/247679/12631904
c aja_mar.c
//程序实例8_1
//邻接矩阵的生成
#include
#include
#define Infinite 9999
#define Max 100
int A[Max][Max];
void adjm(int v[][2],int w[],int n,int e,int t)
{
int k,m=0;
www.eeworm.com/read/334088/12642304
m linkexl.m
function linkexl
[filename,pathname]=uigetfile(('*.xls'),'choose a file');
str=[pathname filename];
[A,B]=xlsread(str); % matlab自动把字符串和数据放在两个矩阵里。A是数据,B为字符串
x=A(:,5);
y=A(:,8);
subplot(2,1,1)
www.eeworm.com/read/135766/13901140
txt gauss消元法----不选主元.txt
#include
#include
#include
#include
#define max_n 200//阶数
#define precision 0.000001//精度
void matrix1(float a[][max_n],int m,int n)//输入矩阵函数
{
int i,j;
www.eeworm.com/read/203459/15358916
txt pca_program.txt
%---------------------------------------------------------------------------------------------------
%S1,S2,...........Sm是M*N的图像矩阵存于M文件中
%m是样本数存于M文件中
%设共有h类(即h人的照片),每人l张不同的照片,m=h*l
%--------------
www.eeworm.com/read/202952/15369019
txt gauss-jord求逆算发.txt
下面是实现Gauss-Jordan法实矩阵求逆。
#include
#include
#include
int brinv(double a[], int n)
{ int *is,*js,i,j,k,l,u,v;
double d,p;
is=malloc(n*sizeof(int));
js=mal