代码搜索:协方差矩阵

找到约 10,000 项符合「协方差矩阵」的源代码

代码结果 10,000
www.eeworm.com/read/292678/8341302

map hey.map

CodeVisionAVR C Compiler V1.24.8d Professional (C) Copyright 1998-2006 Pavel Haiduc, HP InfoTech s.r.l. http://www.hpinfotech.com File: F:\MCU code\AVR-矩阵键盘\hey.c Global variables memory map:
www.eeworm.com/read/292658/8342655

cpp le_totalchoicegauss.cpp

//LE_TotalChoiceGauss.cpp 全选主元高斯消去法 #include //输入输出流头文件 #include "LinearEquation.h" //线性方程(组)求解头文件 void main() { int i; double a[4][4] = //实系数矩阵 { {0.2368, 0.2471,
www.eeworm.com/read/392415/8343877

m nakagamirnd_gamma.m

function na=nakagamirnd_gamma(m1,N1,N2) %这个函数用gamma分布的方法产生服从Nakagami_m的【N1,N2】维随机矩阵 %-----------------------------2005.5.30 ---------------------------------- % Shuai lujun,Information Engineering
www.eeworm.com/read/392335/8349495

m holderk.m

function [H,u,p]=holderk(x,k) %求householder矩阵Hk n=length(x); if k=n disp('k值错误'); return; end M=max(abs(x)); if M==0 disp('M=0'); return; else x=x/M; end s=norm(
www.eeworm.com/read/367107/9782412

cpp le_totalchoicegauss.cpp

//LE_TotalChoiceGauss.cpp 全选主元高斯消去法 #include //输入输出流头文件 #include "LinearEquation.h" //线性方程(组)求解头文件 void main() { int i; double a[4][4] = //实系数矩阵 { {0.2368, 0.2471,
www.eeworm.com/read/267086/11195392

cpp aic.cpp

#include #include #include #include //矩阵求逆函数 int brinv(double f[],int n) { int *is,*js,i,j,k,l,u,v; double d,p; is=(int *)malloc(n
www.eeworm.com/read/334860/12568025

m inv.m

%求逆矩阵 %用法 B=inv(A) 其中A为数值或符号方阵,B返回A的逆 %例如 % inv([1 2;3 4]) %数值 % syms a b c d;inv([[a,b;c,d]) %符号 % %INV Matrix inverse. % INV(X) is the inverse of the square
www.eeworm.com/read/334860/12568312

m rand.m

%R=rand(m,n) 生成(0,1)上均匀分布的m行n列随机矩阵 %RAND Uniformly distributed random numbers. % RAND(N) is an N-by-N matrix with random entries, chosen from % a uniform distribution on the interval (0.0,1.0
www.eeworm.com/read/248016/12607668

m floyd.m

function [d,path]=floyd(a,sp,ep) % floyd - 最短路问题 % % Syntax: [d,path]=floyd(a,sp,ep) % % Inputs: % a - 距离矩阵是指i到j之间的距离,可以是有向的 % sp - 起点的标号 % ep - 终点的标号 % % Outputs:
www.eeworm.com/read/146618/12631749

cpp aic.cpp

#include #include #include #include //矩阵求逆函数 int brinv(double f[],int n) { int *is,*js,i,j,k,l,u,v; double d,p; is=(int *)malloc(n