代码搜索:协方差矩阵

找到约 10,000 项符合「协方差矩阵」的源代码

代码结果 10,000
www.eeworm.com/read/147529/5728689

m rand.m

%R=rand(m,n) 生成(0,1)上均匀分布的m行n列随机矩阵 %RAND Uniformly distributed random numbers. % RAND(N) is an N-by-N matrix with random entries, chosen from % a uniform distribution on the interval (0.0,1.0
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m inv.m

%求逆矩阵 %用法 B=inv(A) 其中A为数值或符号方阵,B返回A的逆 %例如 % inv([1 2;3 4]) %数值 % syms a b c d;inv([[a,b;c,d]) %符号 % %INV Matrix inverse. % INV(X) is the inverse of the square
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m rand.m

%R=rand(m,n) 生成(0,1)上均匀分布的m行n列随机矩阵 %RAND Uniformly distributed random numbers. % RAND(N) is an N-by-N matrix with random entries, chosen from % a uniform distribution on the interval (0.0,1.0
www.eeworm.com/read/144587/5749638

java jumain.java

class JuSum { float a[ ][ ]={{1,2,3},{4,5,6},{7,8,9}}; float sum=0; float getSum() { System.out.println("矩阵元素:"); for(int i=0;i
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cpp main.cpp

#include #include #include const int MAX_VERTEX_NUM = 20; /* 用邻接矩阵表示的AOV图 */ struct AOVGraph { int vexnum; int matrix[MAX_VERTEX_NUM][MAX_VERTEX_NUM];
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h mex.h

#include "mex.h" void timestwo_alt(double y, double x) { *y=2.0 * x; } void mexFunction(int nlhs,mxArray *plhs[ ],int nrhs,const mxArray *prhs[ ]) { double *x, *y; //为返回参数创建一个1×1的矩阵 plhs
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m zhixinhanshu.m

function [Accuracy]=dingwei(BeaconAmount) BorderLength=100;%正方形区域的边长 UNAmount=60; NodeAmount=UNAmount+BeaconAmount;%网络节点个数 R=50;%节点的通信距离 % D=zeros(NodeAmount,NodeAmount);%未知节电到信标节点距离初始矩阵;Beaco
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txt chenbo.txt

#include char word[][3]={ {'U','V','0'}, {'Q','V','0'}, {'U','Q','0'}, {'Q','Q','1'}};//矩阵表示 char K[]={'S','U','V','Q'};//状态集 char E[]={'a','b'};//有穷字母表 char string[10]; int resu
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java othelloboard.java

//棋盘类,实现电脑走棋和玩家落子 import java.io.*; public class OthelloBoard { private int[][] board; public OthelloBoard()//构造方法 { board = new int[8][8]; //定义与棋盘上的位置相对应的二维矩阵 initializeBoard(); }
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m luzhuigan.m

function [L,U,x]=LUzhuigan(A,f) % 对于带状矩阵的追赶法 n=length(A); a=diag(A)'; b=[diag(A,1)',0]; c=[0,diag(A,-1)']; for i=1:n if i==1 ap(i)=a(i); bp(i)=b(i)/ap(i); y(i,1)=