代码搜索:协方差矩阵
找到约 10,000 项符合「协方差矩阵」的源代码
代码结果 10,000
www.eeworm.com/read/196814/8058588
m inv.m
%求逆矩阵
%用法 B=inv(A) 其中A为数值或符号方阵,B返回A的逆
%例如
% inv([1 2;3 4]) %数值
% syms a b c d;inv([[a,b;c,d]) %符号
%
%INV Matrix inverse.
% INV(X) is the inverse of the square
www.eeworm.com/read/196814/8058828
m rand.m
%R=rand(m,n) 生成(0,1)上均匀分布的m行n列随机矩阵
%RAND Uniformly distributed random numbers.
% RAND(N) is an N-by-N matrix with random entries, chosen from
% a uniform distribution on the interval (0.0,1.0
www.eeworm.com/read/196808/8059281
m excoord.m
function exgcoord=excoord
%------------------------------------------------------------------------
% 目的:
% 将节点坐标从5x5的四分之一板扩充到10x10的全板
%
% 变量:
% exgcoord - 扩充后的节点坐标矩阵
%-------------
www.eeworm.com/read/331866/12803351
m pluslr.m
%----4.18编 增 l减 r法 特征选择
clear;
clc;
%--------特征导入 请自行修改
M=256;N=256;
load coourfeature_0420_FGL-5 %%%共生矩阵 96.14%
feature{1}=coourfeature(:,1);
feature{2}=coourfeature(:,2);
feature{3}=coour
www.eeworm.com/read/244945/12829439
m inv.m
%求逆矩阵
%用法 B=inv(A) 其中A为数值或符号方阵,B返回A的逆
%例如
% inv([1 2;3 4]) %数值
% syms a b c d;inv([[a,b;c,d]) %符号
%
%INV Matrix inverse.
% INV(X) is the inverse of the square
www.eeworm.com/read/244945/12829602
m rand.m
%R=rand(m,n) 生成(0,1)上均匀分布的m行n列随机矩阵
%RAND Uniformly distributed random numbers.
% RAND(N) is an N-by-N matrix with random entries, chosen from
% a uniform distribution on the interval (0.0,1.0
www.eeworm.com/read/243793/12916684
m dfp.m
function opt=DFP()
%
% DFP算法求无约束优化问题的最小值
%
global x p k H
x=[2 2]'; %初始迭代点
H=eye(2); %初始矩阵H0=E
eps=1e-32;
www.eeworm.com/read/329331/12960347
m inv.m
%求逆矩阵
%用法 B=inv(A) 其中A为数值或符号方阵,B返回A的逆
%例如
% inv([1 2;3 4]) %数值
% syms a b c d;inv([[a,b;c,d]) %符号
%
%INV Matrix inverse.
% INV(X) is the inverse of the square
www.eeworm.com/read/329331/12960601
m rand.m
%R=rand(m,n) 生成(0,1)上均匀分布的m行n列随机矩阵
%RAND Uniformly distributed random numbers.
% RAND(N) is an N-by-N matrix with random entries, chosen from
% a uniform distribution on the interval (0.0,1.0
www.eeworm.com/read/328394/13029761
cpp matrix1.cpp
#include
#include
#include
using namespace std;
int main()
{
clock_t start, finish;
clock_t start1, finish1;
int i,j,k;
//初始化两个1000*1000的矩阵