代码搜索:协方差矩阵
找到约 10,000 项符合「协方差矩阵」的源代码
代码结果 10,000
www.eeworm.com/read/167499/9967535
cpp matrix.cpp
#include"Matrix.h"
#include
#include
A::A(int temp_n){
if (temp_n
www.eeworm.com/read/167036/9983900
cpp aic.cpp
#include
#include
#include
#include
//矩阵求逆函数
int brinv(double f[],int n)
{ int *is,*js,i,j,k,l,u,v;
double d,p;
is=(int *)malloc(n
www.eeworm.com/read/166306/10024432
m inv.m
%求逆矩阵
%用法 B=inv(A) 其中A为数值或符号方阵,B返回A的逆
%例如
% inv([1 2;3 4]) %数值
% syms a b c d;inv([[a,b;c,d]) %符号
%
%INV Matrix inverse.
% INV(X) is the inverse of the square
www.eeworm.com/read/166306/10024607
m rand.m
%R=rand(m,n) 生成(0,1)上均匀分布的m行n列随机矩阵
%RAND Uniformly distributed random numbers.
% RAND(N) is an N-by-N matrix with random entries, chosen from
% a uniform distribution on the interval (0.0,1.0
www.eeworm.com/read/165898/10047338
m sumarize8_7_2.m
syms t s %定义基本符号变量
syms a b positive %对常数进行“限定性”设置
Mt = [dirac(t-a),heaviside(t-b);exp(-a*t)*sin(b*t),t^2*cos(3*t)]; %定义输入矩阵
MS = laplace(Mt,
www.eeworm.com/read/358694/10181613
m inv.m
%求逆矩阵
%用法 B=inv(A) 其中A为数值或符号方阵,B返回A的逆
%例如
% inv([1 2;3 4]) %数值
% syms a b c d;inv([[a,b;c,d]) %符号
%
%INV Matrix inverse.
% INV(X) is the inverse of the square
www.eeworm.com/read/358694/10181698
m rand.m
%R=rand(m,n) 生成(0,1)上均匀分布的m行n列随机矩阵
%RAND Uniformly distributed random numbers.
% RAND(N) is an N-by-N matrix with random entries, chosen from
% a uniform distribution on the interval (0.0,1.0
www.eeworm.com/read/358205/10193828
txt 平差程序.txt
#include
#include
using namespace std;
int main()
{
//矩阵转置开始
const int a=5,b=3;
double m[a][b]={
{1,0,0},
{-1,1,0},
{0,1,0},
{0,1,-1},
{0,0,1}};
www.eeworm.com/read/426122/10285411
asv main.asv
function main()
N=10; %城市数
A=1.5; %系数A
D=1;u0=0.02; %系数D
Step_t=0.1; %神经元函数斜率
MaxEpochs=2000; %迭代次数
% 得到城市间距离矩阵
CityCood=rand(2,N);
DistanceMat=dist(C
www.eeworm.com/read/426122/10285415
m main.m
function main()
N=10; %城市数
A=1.5; %系数A
D=1;u0=0.02; %系数D
Step_t=0.1; %神经元函数斜率
MaxEpochs=2000; %迭代次数
% 得到城市间距离矩阵
CityCood=rand(2,N);
DistanceMat=dist(C