代码搜索:协方差矩阵

找到约 10,000 项符合「协方差矩阵」的源代码

代码结果 10,000
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plg 矩阵键盘.plg

礦ision3 Build Log Project: F:\PROTEUS KEILC51 模块仿真\矩阵键盘\矩阵键盘.uv2 Project File Date: 05/16/2008 Output: Build target 'Target 1' compiling 键盘.c
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doc 矩阵转换.doc

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txt 矩阵键盘.txt

#include #define uchar unsigned char #define uint unsigned int uchar code table[]={0xc0,0xf9,0xa4,0xb0, 0x99,0x92,0x82,0xf8, 0x80,0x90,0x88,0x83,
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vbw 矩阵相乘.vbw

Form1 = 44, 44, 577, 491, , 22, 22, 555, 469, C
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vbp 矩阵相乘.vbp

Type=Exe Reference=*\G{00020430-0000-0000-C000-000000000046}#2.0#0#C:\WINDOWS\system32\stdole2.tlb#OLE Automation Form=矩阵想乘.frm Object={5E9E78A0-531B-11CF-91F6-C2863C385E30}#1.0#0; MSFLXGRD.OCX St
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txt 导纳矩阵.txt

(0,-17.3611) (0,0) (0,0) (0,17.3611) (0,0) (0,0) (0,0) (0,0) (0,0) (0,0) (0,-16) (0,0) (0,0) (0,0) (0,0) (0,16) (0,0) (0,0) (0,0) (0,0) (0,-17.0648) (0,0) (0,0) (0,0) (0,0) (0,0) (0,17.0648) (0,
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c 逆矩阵.c

#define N 5 /*[注]:修改6为你所要的矩阵阶数*/ #include "stdio.h" #include "conio.h" /*js()函数用于计算行列式,通过递归算法实现*/ int js(s,n) int s[][N],n; {int z,j,k,r,total=0; int b[N][N];/*b[N][N]用于存放,在矩阵s[
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c 乘法矩阵.c

#include void main() { int i,j; int big[8][8]; for (i = 0;i < 8;i++) /*循环嵌套*/ for (j = 0;j < 8;j++) big[i][j] = i * j; /* 乘法表 */ big[2][6] = 748;
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c 矩阵转换.c

void trans(int *p,int n) { int i,j,temp; int *pi,*pj; for(i=0;i
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cpp 矩阵计算.cpp

#include #include template void inverse(T1 *mat1,T2*mat2,int a,int b); template void multi(T1 *mat1,T2 *mat2,T2 *re,int a,in