代码搜索:协方差矩阵

找到约 10,000 项符合「协方差矩阵」的源代码

代码结果 10,000
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opt 矩阵计算.opt

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dsp 矩阵计算.dsp

# Microsoft Developer Studio Project File - Name="矩阵计算" - Package Owner= # Microsoft Developer Studio Generated Build File, Format Version 6.00 # ** DO NOT EDIT ** # TARGTYPE "Win32 (x86) Cons
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cpp 矩阵计算.cpp

// 矩阵计算.cpp : Defines the entry point for the console application. // #include "stdafx.h" class Matrix { public: int x,y; //x,y分别表示矩阵的列数与行数 double** element; //我们用二维数组来代表矩阵
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ncb 矩阵计算.ncb

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dsw 矩阵计算.dsw

Microsoft Developer Studio Workspace File, Format Version 6.00 # WARNING: DO NOT EDIT OR DELETE THIS WORKSPACE FILE! ###############################################################################
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txt 矩阵相乘.txt

void matrixmultiply(A,B,C) { for(int i=0;i
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cpp 矩阵连乘.cpp

#include int m[1024][1024]; int p[1024]; int main() { int n,r,i,j,k,t; scanf("%d",&n); for(i=0;i
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c 逆矩阵.c

#define N 5 /*[注]:修改6为你所要的矩阵阶数*/ #include "stdio.h" #include "conio.h" /*js()函数用于计算行列式,通过递归算法实现*/ int js(s,n) int s[][N],n; {int z,j,k,r,total=0; int b[N][N];/*b[N][N]用于存放,在矩阵s[
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c 乘法矩阵.c

#include void main() { int i,j; int big[8][8]; for (i = 0;i < 8;i++) /*循环嵌套*/ for (j = 0;j < 8;j++) big[i][j] = i * j; /* 乘法表 */ big[2][6] = 748;
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c 矩阵转换.c

void trans(int *p,int n) { int i,j,temp; int *pi,*pj; for(i=0;i