代码搜索：冲击电钻
找到约 315 项符合「冲击电钻」的源代码
代码结果 315
www.eeworm.com/read/444759/7607516
m 3-12.m
%例程3-12 求解单位冲击响应的幅频
N=20;
a=[0.4 0.3 -1];
b=[1 -0.2 0.6 0.3];
x=[1 zeros(1,N-1)];
k=0:N-1;
y=filter(a,b,x);
Fs=1000;
w=0:pi/Fs:pi;
h=freqz(a,b,w);
subplot(2,1,1);
stem(k,y);
www.eeworm.com/read/440997/7678188
m mimo_channel.m
function f=mimo_channel(Nr,Nt,fd,t)
% 接收天线个数 发射天线个数 最大多普勒频移 时间变量
% 输出 mimo_channel MIMO信道的信道冲击响应。
% 单径信道利用 Jakes 模型仿真。
% 移动速度是3km。
s=35;
%mm=0;
rand('state',0);
for i=1:Nt*Nr
for l=1:
www.eeworm.com/read/399063/7897814
txt e9.14.txt
!----------------------------------------
!EX9.14A 质量块跌落冲击简支梁的瞬态分析
finish
/clear
/config,nres,5000
/prep7
h=4
et,1,mass21,,,4
et,2,beam3
et,3,conta175,,1
et,4,targe169
r,1,10
r,2,1e-4,1e
www.eeworm.com/read/397861/8018280
txt e9.14.txt
!----------------------------------------
!EX9.14A 质量块跌落冲击简支梁的瞬态分析
finish
/clear
/config,nres,5000
/prep7
h=4
et,1,mass21,,,4
et,2,beam3
et,3,conta175,,1
et,4,targe169
r,1,10
r,2,1e-4,1e
www.eeworm.com/read/486198/6538013
m 3-12.m
%例程3-12 求解单位冲击响应的幅频
N=20;
a=[0.4 0.3 -1];
b=[1 -0.2 0.6 0.3];
x=[1 zeros(1,N-1)];
k=0:N-1;
y=filter(a,b,x);
Fs=1000;
w=0:pi/Fs:pi;
h=freqz(a,b,w);
subplot(2,1,1);
stem(k,y);
www.eeworm.com/read/485392/6561187
m 3-12.m
%例程3-12 求解单位冲击响应的幅频
N=20;
a=[0.4 0.3 -1];
b=[1 -0.2 0.6 0.3];
x=[1 zeros(1,N-1)];
k=0:N-1;
y=filter(a,b,x);
Fs=1000;
w=0:pi/Fs:pi;
h=freqz(a,b,w);
subplot(2,1,1);
stem(k,y);
www.eeworm.com/read/341613/12075839
m 3-12.m
%例程3-12 求解单位冲击响应的幅频
N=20;
a=[0.4 0.3 -1];
b=[1 -0.2 0.6 0.3];
x=[1 zeros(1,N-1)];
k=0:N-1;
y=filter(a,b,x);
Fs=1000;
w=0:pi/Fs:pi;
h=freqz(a,b,w);
subplot(2,1,1);
stem(k,y);
www.eeworm.com/read/415746/11055942
m 3-12.m
%例程3-12 求解单位冲击响应的幅频
N=20;
a=[0.4 0.3 -1];
b=[1 -0.2 0.6 0.3];
x=[1 zeros(1,N-1)];
k=0:N-1;
y=filter(a,b,x);
Fs=1000;
w=0:pi/Fs:pi;
h=freqz(a,b,w);
subplot(2,1,1);
stem(k,y);
www.eeworm.com/read/375257/9367049
m f5_16.m
%产生非平稳信号
%%信号1:冲击信号
sig1=anapulse(128);
%%信号2：两个正弦信号的叠加
sig2=fmconst(128,0.15)+fmconst(128,0.35);
%计算信号1的尺度图
[tfr,t,f,wt]=tfrscalo(sig1,1:128,6,0.05,0.45,128,1);
%时频分布
figure(1)
contour(t,f
www.eeworm.com/read/161995/10348340
m f5_16.m
%产生非平稳信号
%%信号1:冲击信号
sig1=anapulse(128);
%%信号2：两个正弦信号的叠加
sig2=fmconst(128,0.15)+fmconst(128,0.35);
%计算信号1的尺度图
[tfr,t,f,wt]=tfrscalo(sig1,1:128,6,0.05,0.45,128,1);
%时频分布
figure(1)
contour(t,f