代码搜索：全差分

找到约 10,000 项符合「全差分」的源代码

代码结果 10,000
热门代码： main.c GPIO I2C SPI UART timer interrupt ADC PWM LED
www.eeworm.com/read/480097/1323061

txt 王敏-2.5分.txt

#include #include #include #include #include #include #include long n;//棋盘的大小 int num;//可放置战车数 char * * chessBoar
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www.eeworm.com/read/480097/1323063

txt 孙锋-6分.txt

#include #include #include int n; int *data; void readData() { ifstream inStream; inStream.open("input.txt"); if(!inStream) { cerr
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txt 郑凌-4.5分.txt

//计算程序的最优存储方案 #include #include using namespace std; float MinTime(int, float*, float*); float MinTime(int n, float *l, float *p) { int i, j; float a=0, b=0, *t;
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www.eeworm.com/read/480097/1323068

txt 周恒-6分.txt

#include #include #include char *x,*y,**b; int **c; ofstream fout("output.txt"); void LCSLength(int m,int n,char *x,char *y,int **c,char **b) { int i,j
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www.eeworm.com/read/480097/1323070

txt 陈星娥-6分.txt

#include < iostream.h > #include < fstream.h > #include < stdio.h > ofstream myoutf("output.txt"); //输出数据到文件, void LISlength(int m,int * x,int * y); void main() { int size; //定义序列的长度 i
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txt 谢富平-6分.txt

#include < stdio.h > #include < fstream.h > #include < iostream.h > ofstream myoutf("output.txt"); int Max_Sum(int m,int n, int * a) { if (n < m || m < 1) return 0; int * b = new int[n +
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txt 陈慧-5分.txt

/*矩阵特征值问题*/ /*本程序在vc++6.0上运行通过,并用 cl.exe 编译通过*/ #include #include void readfile(int&,int*&); void fpshuzhu(int,int**&); void matrix(int*,int,int**&); int max(int,int,int)
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www.eeworm.com/read/480097/1323085

txt 林政-5分.txt

// //学号:040000103 //姓名:林政 // #include < iostream.h > #include < fstream.h > #include < stdio.h > ofstream out_file("output.txt"); //输出文件 int MaxSum(int n,int * a); int MaxSum2(int m,int n,i
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www.eeworm.com/read/480097/1323091

txt 董凌-3分.txt

#include #include #include int n,e; int** value; int* temporder; int calculate() { int leng=0; for (int i=1;i
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www.eeworm.com/read/327496/3455307

c 四分砝码.c

#include #include main() { int weight1,weight2,weight3,weight4,d1,d2,d3,d4,x,flag; printf("The weight is broke up as following 4 pieces:"); for(weight1=1;weight1
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