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人工智能/神经网络 CODE OF NSGA,I hope that it will help you,thank you~

CODE OF NSGA,I hope that it will help you,thank you~
https://www.eeworm.com/dl/650/386760.html
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驱动编程 I want to provide an example file system driver for Windows NT/2000/XP. For some time I have worked

I want to provide an example file system driver for Windows NT/2000/XP. For some time I have worked on an implementation of RomFs. RomFs is a small filesystem originally implemented in Linux, because of its simple disk layout its a good choice for an example driver. The current status is a working r ...
https://www.eeworm.com/dl/618/387261.html
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系统设计方案 if you want to it you can download and i m a student,this is a paper,I m wish it can help you.

if you want to it you can download and i m a student,this is a paper,I m wish it can help you.
https://www.eeworm.com/dl/678/389550.html
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电子书籍 微软公司内部所有工程师的必读之书 I. M. Wright s Hard Code

微软公司内部所有工程师的必读之书 I. M. Wright s Hard Code
https://www.eeworm.com/dl/cadence/ebook/391244.html
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数学计算 数值分析的2个c语言程序 1)I显示方法(2)艾特肯

数值分析的2个c语言程序 1)I显示方法(2)艾特肯
https://www.eeworm.com/dl/641/391591.html
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Java编程 Java I/O操作

Java I/O操作,字节流InputStream和OutputStream,字符流Reader和Writer,Java I/O库的设计原则,字符集的编码,RandomAccessFile类,管道流,对象的序列化。
https://www.eeworm.com/dl/633/392343.html
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电子书籍 WSAASYNCSELECT I / O模型 的程序设计 包括源码及原理等

WSAASYNCSELECT I / O模型 的程序设计 包括源码及原理等
https://www.eeworm.com/dl/cadence/ebook/393140.html
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matlab例程 设计了巴特沃斯、车比雪夫I

设计了巴特沃斯、车比雪夫I,Ⅱ型、椭圆滤波器,并有对心电信号的低通处理。
https://www.eeworm.com/dl/665/393366.html
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数据结构 void Knight(int i , int j) { // printf("%d %dn",i,j) if (board[i][j] != 0 || i < 0 || i >=

void Knight(int i , int j) { // printf("%d %dn",i,j) if (board[i][j] != 0 || i < 0 || i >= Size || j < 0 || j >= Size ) { return } step++ board[i][j]=step if (step == Size*Size) { showboard() system("PAUSE") return } //DFS Knight(i-2,j-1) //left Knight(i-2,j+1) Knight(i+2,j-1) //right ...
https://www.eeworm.com/dl/654/393662.html
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STL int getDivisor(int iNum) { int i = 1 int sum = 0 if (0 == iNum) { return 1 } while

int getDivisor(int iNum) { int i = 1 int sum = 0 if (0 == iNum) { return 1 } while (i <= iNum / 2) { if (0 == iNum % i) { sum++ } i++ } return (sum+1) }
https://www.eeworm.com/dl/658/393667.html
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