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加密解密 基于 xinlinx 写的DES加密算法
基于 xinlinx 写的DES加密算法，内涵test bench，加密解密都有
邮电通讯系统 radius协议源码÷The Radius Stack will connect to a Radius Server. This stack implementation is built upo
radius协议源码÷The Radius Stack will connect to a Radius Server. This stack
implementation is built upon the UdpStack which is available
in the radius{version}/util directory. A minimal set of VSAs (Vendor
Specific Attributes are supported by this stack). The Radius
Stack should be used as a base c ...
Java编程 openfans 0.1 using: eclipse, maven, spring, hibernate, mysql,common-validator,sitemesh.....
openfans 0.1
using: eclipse, maven, spring, hibernate,
mysql,common-validator,sitemesh.....
Introduction
============
提供web2.0应用的基本模型,能够方便的在各个领域使用
Getting Started
===============
需要下载maven，http://maven.apache.org/download.html，如果初次使用maven，配置好后，运行mvn insta ...
汇编语言 This directory contains the memtest 8051 firmware for the Anchor Chips EZ-USB chip. The purpose
This directory contains the memtest 8051 firmware
for the Anchor Chips EZ-USB chip.
The purpose of this software is to test the different
memory segments in the Ez-Usb chip.
This example will output the string "good" on the 7 segment
LED if the mem test passes, or it will output the first addres ...
汇编语言 The purpose of this example is to demonstrate that the functioning of External interrupts (INT0, IN
The purpose of this example is to demonstrate that the
functioning of External interrupts (INT0, INT1, INT4, INT5 and INT6) and
how toset them up.
This directory contains the frameworks fw.c, the test program extr_intr.c
and the external interrupt service routines isr.c. This was compiled
using m ...
嵌入式Linux Linux 2.4.18 s3c2440 led driver 使用dev-C++撰寫
Linux 2.4.18 s3c2440 led driver
使用dev-C++撰寫，需要linux 2.4.18 kernel include，編譯完成後產生led module。
insmod main.o //安裝模組
mknod /dev/leds c 221 0
使用方法：
int main(int argc, char *argv[])
{
int testdev
//led test...
testdev = open("/dev/QuickMarkLed",O_RDWR)
ioctl(testdev, 2 ...
Java编程 We have a group of N items (represented by integers from 1 to N), and we know that there is some tot
We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparis ...
微处理器开发 1305时钟芯片驱动
1305时钟芯片驱动，用于弹片机、dsp、msp开发时的计时。
Linux/Unix编程 This a naive implementation of BOOTP/TFTPBOOT, the protocols to use to bootstrap a computer through
This a naive implementation of BOOTP/TFTPBOOT, the protocols
to use to bootstrap a computer through a TCP/IP network.
The goal was to design a small footprint implementation
to allow the code to be integrated into a monitor program
stored in a ROM/FLASH, the footprint is about 7 KBytes
for the test ...