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找到约 145 项符合 math 的查询结果

人工智能/神经网络 mani: MANIfold learning demonstration GUI by Todd Wittman, Department of Mathematics, University of

mani: MANIfold learning demonstration GUI by Todd Wittman, Department of Mathematics, University of Minnesota E-mail wittman@math.umn.edu with comments & questions. MANI Website: httP://www.math.umn.edu/~wittman/mani/index.html Last Modified by GUIDE v2.5 10-Apr-2005 13:28:36 Methods obtained from v ...
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matlab例程 private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoin

private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoint.Y > AOrigin.Y) return Math.PI * 0.5f else return Math.PI * 1.5f else if (APoint.Y == AOrigin.Y) if (APoint.X > AOrigin.X) return 0 else return Math.PI else {
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加密解密 private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoin

private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoint.Y > AOrigin.Y) return Math.PI * 0.5f else return Math.PI * 1.5f else if (APoint.Y == AOrigin.Y) if (APoint.X > AOrigin.X) return 0 else return Math.PI else {
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加密解密 private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoin

private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoint.Y > AOrigin.Y) return Math.PI * 0.5f else return Math.PI * 1.5f else if (APoint.Y == AOrigin.Y) if (APoint.X > AOrigin.X) return 0 else return Math.PI else {
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单片机开发 51单片连tcs230的源程序

51单片连tcs230的源程序,绝对原创,可以记忆颜色。 #define uchar unsigned char #include <reg52.h> #include<math.h> sbit S0=P1^7 sbit S1=P1^0 //端口定义 sbit S2=P1^1 sbit S3=P1^2 sbit OE=P1^3 sbit OUT=P3^4 //频率从TO口输入 sbit key0=P1^5 sbit LED=P1^6 sbit a=P3^0 sbit b=P3^1 uchar color //1: ...
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matlab例程 这是书上的代码

这是书上的代码,C/C++中调用Matlab C Math Library的实现,供大家参考
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游戏 <1>学习3D中的地形.pdf <2>Mathematics.for.3D.Game.Programming.and.Computer.Graphics.2E.July.20

<1>学习3D中的地形.pdf <2>Mathematics.for.3D.Game.Programming.and.Computer.Graphics.2E.July.2005.pdf <3>向量在游戏中的应用.pdf <4>3D-Math-Primer for graphics and game development.pdf 这我所找到相关游戏开发过程,可能遇到的3d游戏方面数学上的资料! ...
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微处理器开发 200-MHz ARM920T Processor &#8226 16-kbyte Instruction Cache &#8226 16-kbyte Data Cache &#8226

200-MHz ARM920T Processor &#8226 16-kbyte Instruction Cache &#8226 16-kbyte Data Cache &#8226 Linux&reg , Microsoft&reg Windows&reg CE-enabled MMU &#8226 100-MHz System Bus &#8226 MaverickCrunch&#8482 Math Engine &#8226 Floating Point, Integer, and Signal Processing Instructions &#8226 Opt ...
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文件格式 java面试笔试题大汇总 ~很全面 java面试笔试题大汇总 第一

java面试笔试题大汇总 ~很全面 java面试笔试题大汇总 第一,谈谈final, finally, finalize的区别。   最常被问到。   第二,Anonymous Inner Class (匿名内部类) 是否可以extends(继承)其它类,是否可以implements(实现)interface(接口)?   第三,Static Nested Class 和 Inner Class的不同,说得越多越好(面试 ...
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Java编程 Generate Possion Dis. step1:Generate a random number between [0,1] step2:Let u=F(x)=1-[(1/

Generate Possion Dis. step1:Generate a random number between [0,1] step2:Let u=F(x)=1-[(1/e)x] step3:Slove x=1/F(u) step4:Repeat Step1~Step3 by using different u,you can get x1,x2,x3,...,xn step5:If the first packet was generated at time [0], than the second packet will be generated at time ...
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