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人工智能/神经网络 mani: MANIfold learning demonstration GUI by Todd Wittman, Department of Mathematics, University of
mani: MANIfold learning demonstration GUI by Todd Wittman, Department of Mathematics, University of Minnesota E-mail wittman@math.umn.edu with comments & questions.
MANI Website: httP://www.math.umn.edu/~wittman/mani/index.html
Last Modified by GUIDE v2.5 10-Apr-2005 13:28:36
Methods obtained from v ...
matlab例程 private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoin
private double PointToAngle(Point AOrigin, Point APoint)
{
if (APoint.X == AOrigin.X)
if (APoint.Y > AOrigin.Y)
return Math.PI * 0.5f
else return Math.PI * 1.5f
else if (APoint.Y == AOrigin.Y)
if (APoint.X > AOrigin.X)
return 0
else return Math.PI
else
{
加密解密 private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoin
private double PointToAngle(Point AOrigin, Point APoint)
{
if (APoint.X == AOrigin.X)
if (APoint.Y > AOrigin.Y)
return Math.PI * 0.5f
else return Math.PI * 1.5f
else if (APoint.Y == AOrigin.Y)
if (APoint.X > AOrigin.X)
return 0
else return Math.PI
else
{
加密解密 private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoin
private double PointToAngle(Point AOrigin, Point APoint)
{
if (APoint.X == AOrigin.X)
if (APoint.Y > AOrigin.Y)
return Math.PI * 0.5f
else return Math.PI * 1.5f
else if (APoint.Y == AOrigin.Y)
if (APoint.X > AOrigin.X)
return 0
else return Math.PI
else
{
单片机开发 51单片连tcs230的源程序
51单片连tcs230的源程序,绝对原创,可以记忆颜色。
#define uchar unsigned char
#include <reg52.h>
#include<math.h>
sbit S0=P1^7
sbit S1=P1^0 //端口定义
sbit S2=P1^1
sbit S3=P1^2
sbit OE=P1^3
sbit OUT=P3^4 //频率从TO口输入
sbit key0=P1^5
sbit LED=P1^6
sbit a=P3^0
sbit b=P3^1
uchar color //1: ...
游戏 <1>学习3D中的地形.pdf <2>Mathematics.for.3D.Game.Programming.and.Computer.Graphics.2E.July.20
<1>学习3D中的地形.pdf
<2>Mathematics.for.3D.Game.Programming.and.Computer.Graphics.2E.July.2005.pdf
<3>向量在游戏中的应用.pdf
<4>3D-Math-Primer for graphics and game development.pdf
这我所找到相关游戏开发过程,可能遇到的3d游戏方面数学上的资料! ...
微处理器开发 200-MHz ARM920T Processor • 16-kbyte Instruction Cache • 16-kbyte Data Cache •
200-MHz ARM920T Processor
&#8226 16-kbyte Instruction Cache
&#8226 16-kbyte Data Cache
&#8226 Linux&reg , Microsoft&reg Windows&reg CE-enabled MMU
&#8226 100-MHz System Bus
&#8226 MaverickCrunch&#8482 Math Engine
&#8226 Floating Point, Integer, and Signal Processing
Instructions
&#8226 Opt ...
文件格式 java面试笔试题大汇总 ~很全面 java面试笔试题大汇总 第一
java面试笔试题大汇总 ~很全面
java面试笔试题大汇总
第一,谈谈final, finally, finalize的区别。
最常被问到。
第二,Anonymous Inner Class (匿名内部类) 是否可以extends(继承)其它类,是否可以implements(实现)interface(接口)?
第三,Static Nested Class 和 Inner Class的不同,说得越多越好(面试 ...
Java编程 Generate Possion Dis. step1:Generate a random number between [0,1] step2:Let u=F(x)=1-[(1/
Generate Possion Dis.
step1:Generate a random number between [0,1]
step2:Let u=F(x)=1-[(1/e)x]
step3:Slove x=1/F(u)
step4:Repeat Step1~Step3 by using different u,you can get x1,x2,x3,...,xn
step5:If the first packet was generated at time [0], than the
second packet will be generated at time ...