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求一个较大数的阶乘！例如100！将超过long的表示范围，本程序将告诉你一种简单而有效的方法。

long bei ge suan fa 龙算法

long range dependent alaysis

In this first-ever paperback edition of his long-time best-seller, motivational speaker Steve Chandler helps you create an action plan for living your vision in business and in life. It features 100 proven methods to positively change the way you think and act-methods based on feedback from the hund ...

oracle long raw类型，图像的批量导出工具，可，导出图像数据。。且自动分文件夹

C++ Template Metaprogramming sheds light on the most powerful idioms of today s C++, at long last delivering practical metaprogramming tools and techniques into the hands of the everyday programmer. A metaprogram is a program that generates or manipulates program code. Ever since generic programmi ...

Ajax, the popular term for Asynchronous JavaScript and XML, is one of the most important combinations of technologies for web developers to know these days. With its rich grouping of technologies, Ajax developers can create interactive web applications with XML-based web services, using JavaScript i ...

编写如下方法：求一个长整数的各位数之和：public static int qiuhe(long s) 找10～100之间能被３或５整除的数，每行输出5个数。

实现int或long int类型数据向time类型数据转化，比如说，int i=258147369, 它将转化为x小时y分z秒。

#include<iostream> using namespace std int main() { unsigned long x,warcraft,war,l cin> x while(x) { unsigned long *p=new unsigned long[x+1] if(p==NULL) { cerr<<"error!"<<endl abort() } for(warcraft=0 warcraft<=x warcraft++) *(p+warcraft)=0 *p=1 for(warcraft=0 war ...