搜索结果
找到约 110 项符合
integer 的查询结果
按分类筛选
- 全部分类
- 技术资料 (9)
- Java编程 (9)
- 数学计算 (8)
- 数据结构 (7)
- Delphi控件源码 (7)
- 其他 (6)
- 源码 (4)
- 单片机编程 (4)
- 其他书籍 (4)
- 压缩解压 (4)
- 单片机开发 (4)
- matlab例程 (4)
- 数值算法/人工智能 (3)
- DSP编程 (2)
- 加密解密 (2)
- 书籍源码 (2)
- 模拟电子 (2)
- 教程资料 (2)
- 可编程逻辑 (2)
- Internet/网络编程 (2)
- 编译器/解释器 (2)
- Applet (2)
- 人工智能/神经网络 (2)
- Delphi/CppBuilder (2)
- 软件工程 (1)
- 电子书籍 (1)
- Mentor (1)
- 语音压缩 (1)
- 其他数据库 (1)
- 嵌入式/单片机编程 (1)
- 微处理器开发 (1)
- VHDL/FPGA/Verilog (1)
- 系统设计方案 (1)
- Oracle数据库 (1)
- 软件设计/软件工程 (1)
- JavaScript (1)
- SQL Server (1)
- 并行计算 (1)
- VIP专区 (1)
编译器/解释器 构造一个简单程序设计语言的词法分析器
构造一个简单程序设计语言的词法分析器,要求:
1) 含有保留字program, begin, end, var, integer, if, then, else, do, while.
2) 标识符和无符号的整常数,其中保留字和标识符不区分大小写.
3) 含有界符和运算符如下:+,-, (, ), =, >, <, , :, :=.,,。
4) 输出二元组。 ...
语音压缩 The Audio File Library provides a uniform programming interface to standard digital audio file form
The Audio File Library provides a uniform programming interface to
standard digital audio file formats.
This library allows the processing of audio data to and from audio
files of many common formats (currently AIFF, AIFF-C, WAVE, NeXT/Sun
.snd/.au, IRCAM, AVR, Amiga IFF/8SVX, and NIST SPHERE). The ...
数据结构 2^x mod n = 1 acm竞赛题 Give a number n, find the minimum x that satisfies 2^x mod n = 1. Input
2^x mod n = 1 acm竞赛题 Give a number n, find the minimum x that satisfies 2^x mod n = 1.
Input
One positive integer on each line, the value of n.
Output
If the minimum x exists, print a line with 2^x mod n = 1.
Print 2^? mod n = 1 otherwise.
You should replace x and n with specific numbers. ...
单片机开发 实用的单片机开发与应用程序
实用的单片机开发与应用程序,包括:中值滤波子程序,AD转换类程序,16、32位整型数开方,单片机音乐程序--祝你平安。对初学者很有帮助的。MCU development and practical applications, including: median filter subroutine, AD converter type of proceeding, 16,32-bit integer number prescribing, SCM music program ...
matlab例程 多目标遗传算法程序 to run Demo files, is to run SGALAB_demo_*.m what s new: 1) Multiple-Objective GAs
多目标遗传算法程序
to run Demo files, is to run SGALAB_demo_*.m
what s new:
1) Multiple-Objective GAs
VEGA
NSGA
NPGA
MOGA
2) More TSP mutation and Crossover methods
PMX
OX
CX
EAX
Boolmatrix
3) More selection methods
Truncation
tornament
stochastic
4) mutation methods
binary single point
int/r ...
Applet a Java program that reads in the following values from the standard input device (i.e. Keyboard) an
a Java program that reads in the following values from the standard input device (i.e.
Keyboard) and writes its result on the standard output device (i.e. Console/Monitor):
Inputs:
A: the loan amount in dollars and cents (e.g. 150000.00).
r: the net annual interest rate, expressed as an integer (e.g ...
编译器/解释器 编译原理词法和语法分析
编译原理词法和语法分析,体内容是产生一个二元式文本文件,扩展名为dyd,可将Pascal程序(测试程序)分解成为一个一个的单词,并查“单词符号与种别对照表”得出其种别,用一数字表示,范围1-56(52-56分别对应保留字integer、real、boolean、char)。 ...
Delphi/CppBuilder unit Video interface uses Windows, Messages, SysUtils, Classes, Graphics, Controls, stdctrl
unit Video
interface
uses
Windows, Messages, SysUtils, Classes, Graphics, Controls, stdctrls,
ExtCtrls, avicap, mmsystem, dsgnintf
// Types for event-procedures
type
TCapStatusProc = procedure(Sender: TObject) of object
TCapStatusCallback = procedure(Sender: TObject nID: integer status: st ...
DSP编程 This programme is to control DC motor in a certain speed using PWM. The target speed is "r", it is
This programme is to control DC motor in a certain speed using PWM.
The target speed is "r", it is the speed in 1s.
The sample rate is 0.1s, so the actual speed target is "rc"=r/10.
The "r" and "rc" are integer, and the range of "r" is from 50 to 100.
Keep rc=r/10!!!
The array "speed1" and "speed2" ...
数据结构 HDOJ ACM input:The input consists of T test cases. The number of test cases ) (T is given in the fi
HDOJ ACM
input:The input consists of T test cases. The number of test cases ) (T is given in the first line of the input. Each test case begins with a line containing an integer N , 1<=N<=200 , that represents the number of tables to move. Each of the following N lines contains two positive integers ...