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压缩解压 this the source code of audio compression standard LPC. It is coded by C.
this the source code of audio compression standard LPC. It is coded by C.
压缩解压 1.Xvid Mpeg4 1.13 version 2.Building 0 error(s), 0 warning(s) By Jesse Stone Taiwan
1.Xvid Mpeg4 1.13 version
2.Building 0 error(s), 0 warning(s)
By Jesse Stone Taiwan
其他书籍 An Overview of the Coherent Acoustics Coding System(by Mike Smyth) 一本讲DTS编码细节的书,深入浅出
An Overview of the Coherent Acoustics Coding System(by Mike Smyth) 一本讲DTS编码细节的书,深入浅出
Java编程 Abstract The Lucene Server project is an attempt to extend the Jakarta Lucene tool with server ca
Abstract
The Lucene Server project is an attempt to extend the Jakarta Lucene tool with server capabilities.
Lucene is a robust Java API that enables you creating indexes from text sources and perform powerful searches on these indexes. With Lucene, creating an index must be done programmatically ...
其他嵌入式/单片机内容 show 0-F cycle by cycle in ARM7
show 0-F cycle by cycle in ARM7
技术管理 keil study book by chen yi fan
keil study book by chen yi fan
Java编程 *水季JSP环境探针 v1.1 * *Copyright (C) 2005 by 水季 * *E-mail:water-season@sohu.com * *QQ:176291935 * *h
*水季JSP环境探针 v1.1 *
*Copyright (C) 2005 by 水季 *
*E-mail:water-season@sohu.com *
*QQ:176291935 *
*http://bbs.iaiai.com *
*------------------------------------------------------------------------------------*
*警告:请不要随便修改以上版权信息! *
其他书籍 Microsoft.NET测试驱动开发 Test-Driven Development in Microsoft .NET by James W. Newkirk and Alexei A.
Microsoft.NET测试驱动开发
Test-Driven Development in Microsoft .NET
by James W. Newkirk and Alexei A. Vorontsov ISBN:0735619484
Microsoft Press &copy 2004
Using a wealth of pragmatic examples in C# and other .NET development tools, the two authors of this text demonstrate how to use automated te ...
Java编程 We have a group of N items (represented by integers from 1 to N), and we know that there is some tot
We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparis ...
Java书籍 winsocket 开发指南,Java sockets 101 Presented by developerWorks, your source for great tutorials
winsocket 开发指南,Java sockets 101
Presented by developerWorks, your source for great tutorials