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加密解密 private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoin
private double PointToAngle(Point AOrigin, Point APoint)
{
if (APoint.X == AOrigin.X)
if (APoint.Y > AOrigin.Y)
return Math.PI * 0.5f
else return Math.PI * 1.5f
else if (APoint.Y == AOrigin.Y)
if (APoint.X > AOrigin.X)
return 0
else return Math.PI
else
{
加密解密 private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoin
private double PointToAngle(Point AOrigin, Point APoint)
{
if (APoint.X == AOrigin.X)
if (APoint.Y > AOrigin.Y)
return Math.PI * 0.5f
else return Math.PI * 1.5f
else if (APoint.Y == AOrigin.Y)
if (APoint.X > AOrigin.X)
return 0
else return Math.PI
else
{
其他 For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 3
For solving the following problem:
"There is No Free Lunch"
Time Limit: 1 Second Memory Limit: 32768 KB
One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That ...
其他 一个模糊控制器的仿真设计
一个模糊控制器的仿真设计，被控对象为某离心机，本例采用Fuzzy，Simulink进行仿真设计，最后给出被控对象的输出响应曲线。
单片机开发 Semantic analysis of multimedia content is an on going research area that has gained a lot of atten
Semantic analysis of multimedia content is an on going research
area that has gained a lot of attention over the last few years.
Additionally, machine learning techniques are widely used for multimedia
analysis with great success. This work presents a combined approach
to semantic adaptation of neur ...
matlab例程 it is a simulation about ML synchronization algorithm in OFDM systems,you can slao see a function pi
it is a simulation about ML synchronization algorithm in OFDM systems,you can slao see a function picture in its output,that s useful for a beginner
其他 Euler函数: m = p1^r1 * p2^r2 * …… * pn^rn ai >= 1 , 1 <= i <= n Euler函数： 定义：phi(m) 表示小于等
Euler函数:
m = p1^r1 * p2^r2 * …… * pn^rn ai >= 1 , 1 <= i <= n
Euler函数：
定义：phi(m) 表示小于等于m并且与m互质的正整数的个数。
phi(m) = p1^(r1-1)*(p1-1) * p2^(r2-1)*(p2-1) * …… * pn^(rn-1)*(pn-1)
= m*(1 - 1/p1)*(1 - 1/p2)*……*(1 - 1/pn)
= p1^(r1-1)*p2^(r2-1)* …… * pn^(rn-1 ...
书籍源码 计算全息close all clc clear A=zeros(64) A(15:20,20:40)=1 A(15:50,20:25)=1 A(45:50,20:40)=1 A(30:34,
计算全息close all clc clear
A=zeros(64)
A(15:20,20:40)=1 A(15:50,20:25)=1
A(45:50,20:40)=1 A(30:34,20:35)=1
％ ppp=exp(rand(64)*pi*2*i) A=A.*ppp
％ Author s email: zjliu2001@163.com
figure imshow(abs(A),[])
Fa=fft2(fftshift(A)) Fs=fftshift(Fa)
Am=abs(Fs) ％ amplitude
Ph=angle(Fs) ％ phase
s=11 ...
数学计算 // 入口参数： // l: l = 0, 傅立叶变换 l = 1, 逆傅立叶变换 // il: il = 0,不计算傅立叶变换或逆变换模和幅角；il = 1,计算模和幅角 // n: 输入的
// 入口参数：
// l: l = 0, 傅立叶变换 l = 1, 逆傅立叶变换
// il: il = 0,不计算傅立叶变换或逆变换模和幅角；il = 1,计算模和幅角
// n: 输入的点数，为偶数，一般为32，64，128，...,1024等
// k: 满足n=2^k(k>0),实质上k是n个采样数据可以分解为偶次幂和奇次幂的次数
// pr[]: l=0时，存放N点采样数据的实部
// l=1 ...