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通讯/手机编程 SMS-Man is a set of cross-platformed utilities for SMS sending. You can organize SMS-list , SMS aler

SMS-Man is a set of cross-platformed utilities for SMS sending. You can organize SMS-list , SMS alert system (useful for system administrators) and much more.
https://www.eeworm.com/dl/527/159261.html
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matlab例程 a very good programming soft please come here and download it . Believe it or not

a very good programming soft please come here and download it . Believe it or not
https://www.eeworm.com/dl/665/159263.html
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文章/文档 cp2102 is a Single-Chip USB to UART Data Transfer

cp2102 is a Single-Chip USB to UART Data Transfer
https://www.eeworm.com/dl/652/159278.html
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Java书籍 java in a nutshell

java in a nutshell,一本最基础的java书,
https://www.eeworm.com/dl/656/159389.html
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语音压缩 G711/G723/G726/g728/g729 a语音压缩算法的资料及原程序

G711/G723/G726/g728/g729 a语音压缩算法的资料及原程序
https://www.eeworm.com/dl/627/159485.html
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其他 Can Simply add the class to a project rather than (1) reference an activeX DLL or (2) add an ActiveX

Can Simply add the class to a project rather than (1) reference an activeX DLL or (2) add an ActiveX component.
https://www.eeworm.com/dl/534/159518.html
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数据结构 This a program to implement the so-called "dancing link" which is introduced in Knuth s paper. This

This a program to implement the so-called "dancing link" which is introduced in Knuth s paper. This is really a super acrobatic and I am sure that not many programmers can understand the algorithms.  
https://www.eeworm.com/dl/654/159528.html
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数据结构 2^x mod n = 1 acm竞赛题 Give a number n, find the minimum x that satisfies 2^x mod n = 1. Input

2^x mod n = 1 acm竞赛题 Give a number n, find the minimum x that satisfies 2^x mod n = 1. Input One positive integer on each line, the value of n. Output If the minimum x exists, print a line with 2^x mod n = 1. Print 2^? mod n = 1 otherwise. You should replace x and n with specific numbers. ...
https://www.eeworm.com/dl/654/159576.html
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Java编程 随即产生8个a-z和A-Z和0-9的字符串

随即产生8个a-z和A-Z和0-9的字符串
https://www.eeworm.com/dl/633/159583.html
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其他 某幼儿园按如下方法依次给A

某幼儿园按如下方法依次给A,B,C,D,E五个小孩发糖果。将全部糖果的一半再加二分之一块糖果发给第一个小孩;将剩下糖果的三分之一再加三分之一块糖果发给第二个小孩;将剩下糖果的四分之一再加四分之一块糖果发给第三个小孩;将剩下糖果的五分之一再加五分之一块糖果发给第四个小孩;将最后剩下的11块糖果发给第五个小孩 ...
https://www.eeworm.com/dl/534/159638.html
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