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数据结构 out< "please input the number of the nodes"<<endl cin>>nodesNum cout<<"pl

out< "please input the number of the nodes"<<endl cin>>nodesNum cout<<"please input the graph"<<endl for( i = 1 i<=nodesNum i++) for( j = 1 j <= nodesNum j++) cin>>graph[i][j] */
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数据结构 这个课程项目计算了strahler number; 这个很有利于理解二叉树和链表。

这个课程项目计算了strahler number; 这个很有利于理解二叉树和链表。
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其他 设计有理数类rational_number &#61656 数据成员: int numerator(分子) int denominator(分母) &#61656 成员函数 (

设计有理数类rational_number &#61656 数据成员: int numerator(分子) int denominator(分母) &#61656 成员函数 (1)构造函数rational_number ()和rational_number (int x, int y) (2)拷贝构造函数 (3) 重载运算符“+”、“-”、“*”和“/” 2. 设计有理数类rational_number &#61656 数据成员: int n ...
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文章/文档 All 3G and GSM specifications have a 3GPP specification number consisting of 4 or 5 digits. (e.g. 09

All 3G and GSM specifications have a 3GPP specification number consisting of 4 or 5 digits. (e.g. 09.02 or 29.002). The first two digits define the series as listed in the table below. They are followed by 2 further digits for the 01 to 13 series or 3 further digits for the 21 to 55 series. The term ...
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人工智能/神经网络 来自澳大利亚Qeensland大学的计算机视觉Matlab工具箱。 This Toolbox provides a number of functions that are useful in co

来自澳大利亚Qeensland大学的计算机视觉Matlab工具箱。 This Toolbox provides a number of functions that are useful in computer vision, machine vision and related areas. It is a somewhat eclectic collection reflecting the author s personal interest in areas of photometry, photogrammetry, colorimetry. It ...
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邮电通讯系统 输入数组(int[] number)作为sort的参数调用sort 即可实现排序(不减序排列) //或者利用重载的sort方法

输入数组(int[] number)作为sort的参数调用sort 即可实现排序(不减序排列) //或者利用重载的sort方法,输入参数是(int[] number, 0, number.length-1)
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数据结构 2^x mod n = 1 acm竞赛题 Give a number n, find the minimum x that satisfies 2^x mod n = 1. Input

2^x mod n = 1 acm竞赛题 Give a number n, find the minimum x that satisfies 2^x mod n = 1. Input One positive integer on each line, the value of n. Output If the minimum x exists, print a line with 2^x mod n = 1. Print 2^? mod n = 1 otherwise. You should replace x and n with specific numbers. ...
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数值算法/人工智能 随机数 fortran90 L Ecuyer s 1999 random number generator. Fortran version by Alan.Miller @ vic.cmis.cs

随机数 fortran90 L Ecuyer s 1999 random number generator. Fortran version by Alan.Miller @ vic.cmis.csiro.a
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Java编程 Generate Possion Dis. step1:Generate a random number between [0,1] step2:Let u=F(x)=1-[(1/

Generate Possion Dis. step1:Generate a random number between [0,1] step2:Let u=F(x)=1-[(1/e)x] step3:Slove x=1/F(u) step4:Repeat Step1~Step3 by using different u,you can get x1,x2,x3,...,xn step5:If the first packet was generated at time [0], than the second packet will be generated at time ...
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单片机开发 该程序用以查找任意两个整数之间的所有素数。 Prime number finder can find all primes between a and b and will write the res

该程序用以查找任意两个整数之间的所有素数。 Prime number finder can find all primes between a and b and will write the results to the file PRIMES.TXT
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