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找到约 136 项符合 Mid-square 的查询结果

FlashMX/Flex源码 Flash写的小RPG游戏。。。。 # Archive D:ITsource_code1gameRPG.rar effectenemy

Flash写的小RPG游戏。。。。 # Archive D:\IT\source_code\1game\RPG.rar effect\enemy\0.fla effect\enemy\0.swf effect\enemy effect\hero\1.fla effect\hero\1.swf effect\hero\0.swf effect\hero effect error\error.fla error\error.swf error magic\magic1.fla magic\magic2.fla magic\magic3.fla magic\magic4.fla m ...
https://www.eeworm.com/dl/661/250174.html
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matlab例程 Comparison of the performances of the LS and the MMSE channel estimators for a 64 sub carrier OFDM

Comparison of the performances of the LS and the MMSE channel estimators for a 64 sub carrier OFDM system based on the parameter of Mean square error
https://www.eeworm.com/dl/665/253863.html
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Java书籍 thinkinjava2English Thinking in Java, 2nd Edition, Release 11 To be published by Prentice-Hall mi

thinkinjava2English Thinking in Java, 2nd Edition, Release 11 To be published by Prentice-Hall mid-June, 2000 Bruce Eckel, President, MindView, Inc. Planet PDF brings you the Portable Document Format (PDF) version of Thinking in Java (2nd Edition). Planet PDF is the premier PDF-related site on the w ...
https://www.eeworm.com/dl/656/253901.html
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游戏 Ink Blotting One method for escaping from a maze is via ‘ink-blotting’. In this method your startin

Ink Blotting One method for escaping from a maze is via ‘ink-blotting’. In this method your starting square is marked with the number ‘1’. All free, valid squares north, south, east and west around the number ‘1‘ are marked with a number ‘2’. In the next step, all free, valid squares around ...
https://www.eeworm.com/dl/625/254453.html
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其他书籍 Noncoherent receivers are attractive for pulsed UWB systems due to the implementation simplicity. To

Noncoherent receivers are attractive for pulsed UWB systems due to the implementation simplicity. To alleviate the noise effect in detecting UWB PPM signals, this letter proposes a simple yet flexible weighted noncoherent receiver structure, which adopts a square-law integrator multiplied with a win ...
https://www.eeworm.com/dl/542/283591.html
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软件设计/软件工程 Abstract Based on the demand analysis of the RFID middleware

Abstract Based on the demand analysis of the RFID middleware,it suggests how to develop the RFID middle— ware,including the functionality and the mechanism of the event handle,and prospects the future of the RFID mid— dleware.
https://www.eeworm.com/dl/684/296110.html
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游戏 《游戏编程入门》一书16个例子的源码

《游戏编程入门》一书16个例子的源码,但没有加入MID声音代码
https://www.eeworm.com/dl/625/310183.html
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单片机开发 Its functions are: n order within (excluding n) At the same time, 3 and 7 can be integral to all nat

Its functions are: n order within (excluding n) At the same time, 3 and 7 can be integral to all natural and a few of the square root of s, and function as a value to return, the final result s output to file out.dat China.
https://www.eeworm.com/dl/648/365543.html
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Java书籍 《Java手機程式設計入門》/王森 書號:29014 頁數:約 492 頁 ISBN:957-200-527-8 出版日期:2001年08月25日 出版廠商:知城數位科技股份有限

《Java手機程式設計入門》/王森 書號:29014 頁數:約 492 頁 ISBN:957-200-527-8 出版日期:2001年08月25日 出版廠商:知城數位科技股份有限公司 訂價:380 第一章 Java 2 Micro Edition概論阵 第二章 Java程式設計簡介阵 第三章 撰寫您的第一個手機程式阵 第四章 在實體機器上執行MIDlet阵 第五章 J2ME W ...
https://www.eeworm.com/dl/656/373379.html
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人工智能/神经网络 河內塔問題 #include<stdio.h> #include<stdlib.h> int fun_a(int) void fun_b(int,int,int,in

河內塔問題 #include<stdio.h> #include<stdlib.h> int fun_a(int) void fun_b(int,int,int,int) int main(void) { int n int option printf("題目二:河內塔問題\n") printf("請輸入要搬移的圓盤數目\n") scanf("%d",&n) printf("最少搬移的次數為%d次\n",fun_a(n)) printf("是否顯示移動過程? 是請輸入1, ...
https://www.eeworm.com/dl/650/376204.html
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