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找到约 156 项符合 ELSE 的查询结果

编译器/解释器 四元式

四元式,递归下降法书写的if。。else条件语句的语法分析及语义分析程序
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matlab例程 private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoin

private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoint.Y > AOrigin.Y) return Math.PI * 0.5f else return Math.PI * 1.5f else if (APoint.Y == AOrigin.Y) if (APoint.X > AOrigin.X) return 0 else return Math.PI else {
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加密解密 private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoin

private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoint.Y > AOrigin.Y) return Math.PI * 0.5f else return Math.PI * 1.5f else if (APoint.Y == AOrigin.Y) if (APoint.X > AOrigin.X) return 0 else return Math.PI else {
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加密解密 private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoin

private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoint.Y > AOrigin.Y) return Math.PI * 0.5f else return Math.PI * 1.5f else if (APoint.Y == AOrigin.Y) if (APoint.X > AOrigin.X) return 0 else return Math.PI else {
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驱动编程 This utility has two views: (a) one view that will show you the entire PnP enumeration tree of devic

This utility has two views: (a) one view that will show you the entire PnP enumeration tree of device objects, including relationships among objects and all the device s reported PnP characteristics, and (b) a second view that shows you the device objects created, sorted by driver name. There is not ...
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数学计算 溫度華氏轉變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void)

溫度華氏轉變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void) { int a=73,b=85,c=66 { if (a>=90) printf("a=A等級!!\n") else if (a>=80) printf("73分=B等級!!\n") else if (a>=70) printf("73分=C等級!!\n") else if (a>=60) printf("73分=D等級!!\n") else if ( ...
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数学计算 溫度華氏轉變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void)

溫度華氏轉變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void) { int a=73,b=85,c=66 { if (a>=90) printf("a=A等級!!\n") else if (a>=80) printf("73分=B等級!!\n") else if (a>=70) printf("73分=C等級!!\n") else if (a>=60) printf("73分=D等級!!\n") else if ( ...
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数据结构 成績顯示三個部份abc #include<stdio.h> #include<stdlib.h> int main(void) { float gread

成績顯示三個部份abc #include<stdio.h> #include<stdlib.h> int main(void) { float gread printf("請輸入分數\n") scanf("%f",&gread) if(gread>=80&&gread<=100) printf("成績為A\n") else if(gread>=60&&gread<=79) { printf("成績為B\n") } else if(gread>=0&&gread<60) { printf("成績為C\n") } else ...
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人工智能/神经网络 河內塔問題 #include<stdio.h> #include<stdlib.h> int fun_a(int) void fun_b(int,int,int,in

河內塔問題 #include<stdio.h> #include<stdlib.h> int fun_a(int) void fun_b(int,int,int,int) int main(void) { int n int option printf("題目二:河內塔問題\n") printf("請輸入要搬移的圓盤數目\n") scanf("%d",&n) printf("最少搬移的次數為%d次\n",fun_a(n)) printf("是否顯示移動過程? 是請輸入1, ...
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人工智能/神经网络 function [U,center,result,w,obj_fcn]= fenlei(data) [data_n,in_n] = size(data) m= 2 % Exponent fo

function [U,center,result,w,obj_fcn]= fenlei(data) [data_n,in_n] = size(data) m= 2 % Exponent for U max_iter = 100 % Max. iteration min_impro =1e-5 % Min. improvement c=3 [center, U, obj_fcn] = fcm(data, c) for i=1:max_iter if F(U)>0.98 break else w_new=eye(in_n,in_n) center1=sum(cent ...
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