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VHDL/FPGA/Verilog High volume USB 2.0 devices will be designed using ASIC technology with embedded USB 2.0 support. F

High volume USB 2.0 devices will be designed using ASIC technology with embedded USB 2.0 support. For full-speed USB devices the operating frequency was low enough to allow data recovery to be handled in a vendors VHDL code, with the ASIC vendor providing only a simple level translator to meet the U ...
https://www.eeworm.com/dl/663/461372.html
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Java编程 Besides enhanced looks and advanced features, one of the best things about Swing is its pluggable lo

Besides enhanced looks and advanced features, one of the best things about Swing is its pluggable look and feel (PLAF). PLAF architecture allows seamless changes in the appearance of an application and the way an application interacts with the user. However, designing and developing a PLAF is much m ...
https://www.eeworm.com/dl/633/462690.html
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单片机开发 This is a Document on how to implement DDS on SX Communication controllers by Rho Enterprises with F

This is a Document on how to implement DDS on SX Communication controllers by Rho Enterprises with Full Hardware Diagram and Software Program.
https://www.eeworm.com/dl/648/465054.html
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Java编程 利用随机数产生1000个0~100之间的考试分数

利用随机数产生1000个0~100之间的考试分数,将其存入一个文本文件中,然后程序从这个文件中读取这1000个考试分数,统计其中各分数段(A[90,100],B[80,90), C[70,80), D[60,70), F[0,60))的人数 、所占百分比,平均分。
https://www.eeworm.com/dl/633/466536.html
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数值算法/人工智能 解方程

解方程,具体见英文描述,给一个连续方程,解出f(x) = 0 在一定范围的解
https://www.eeworm.com/dl/518/468641.html
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数值算法/人工智能 解方程

解方程,给出一个连续函数接f(x)=0的值,前提是给一个附近的值
https://www.eeworm.com/dl/518/468644.html
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数值算法/人工智能 NEWTON-RAPHSON求解一个连续方程

NEWTON-RAPHSON求解一个连续方程,f(X)=0,前提给一个初始值
https://www.eeworm.com/dl/518/468652.html
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数值算法/人工智能 SECANT法求解一个连续方程

SECANT法求解一个连续方程,f(x) = 0,给两个初始值
https://www.eeworm.com/dl/518/468666.html
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数值算法/人工智能 解方程

解方程,给出一个连续函数接f(x)=0的值,前提是给两个附近的值,且符号相反
https://www.eeworm.com/dl/518/468668.html
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Linux/Unix编程 this gcc-g++-3.3.1.tar.gz is a source file of gcc, you can learn more about gcc through this codes f

this gcc-g++-3.3.1.tar.gz is a source file of gcc, you can learn more about gcc through this codes file,
https://www.eeworm.com/dl/619/470713.html
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