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数学计算 大数的模运算。 a^b % m a可以为1000位的大数

大数的模运算。 a^b % m a可以为1000位的大数,b,m在int 范围内
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数据结构 成績顯示三個部份abc #include<stdio.h> #include<stdlib.h> int main(void) { float gread

成績顯示三個部份abc #include<stdio.h> #include<stdlib.h> int main(void) { float gread printf("請輸入分數\n") scanf("%f",&gread) if(gread>=80&&gread<=100) printf("成績為A\n") else if(gread>=60&&gread<=79) { printf("成績為B\n") } else if(gread>=0&&gread<60) { printf("成績為C\n") } else ...
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书籍源码 A novel met hod t o p artially compensate sigma2delta shap ed noise is p rop osed. By injecting t he

A novel met hod t o p artially compensate sigma2delta shap ed noise is p rop osed. By injecting t he comp en2 sation cur rent int o t he p assive loop f ilte r during t he delay time of t he p hase f requency detect or ( PFD) , a maximum reduction of t he p hase noise by about 16dB can be achieved. ...
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Java编程 Generate Possion Dis. step1:Generate a random number between [0,1] step2:Let u=F(x)=1-[(1/

Generate Possion Dis. step1:Generate a random number between [0,1] step2:Let u=F(x)=1-[(1/e)x] step3:Slove x=1/F(u) step4:Repeat Step1~Step3 by using different u,you can get x1,x2,x3,...,xn step5:If the first packet was generated at time [0], than the second packet will be generated at time ...
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Java编程 This present a primer for people who are unfamiliar with the Java language. This introduction is int

This present a primer for people who are unfamiliar with the Java language. This introduction is intended to allow you to develop the Java skills necessary to understand basic programs.
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通讯/手机编程 I. C. Wong, Z. Shen, J. G. Andrews, and B. L. Evans, ``A Low Complexity Algorithm for Proportional R

I. C. Wong, Z. Shen, J. G. Andrews, and B. L. Evans, ``A Low Complexity Algorithm for Proportional Resource Allocation in OFDMA Systems , Proc. IEEE Int. Work. Signal Processing Systems, 针对这篇文章给出的源代码
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JavaScript Calculates if the brackets in a sentence are correctly close. Input consists, one per line, sentenc

Calculates if the brackets in a sentence are correctly close. Input consists, one per line, sentences with brackets, and output say YES if its correctly close, or NO int if its not saying where is the error. Input: ()[]<>(**) (*) (ASA Output: YES NO 2 NO 4
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电子基础 第八章 数字电路技术 A/D,D/A

第八章 数字电路技术 A/D,D/A
https://www.eeworm.com/dianzishu/415/963.html
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电子基础 21世纪大学新型参考教材系列 集成电路A 荒井

21世纪大学新型参考教材系列 集成电路A 荒井
https://www.eeworm.com/dianzishu/415/1025.html
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测试技术 积分式A/D转换器其它专用集成电路分册 清晰书签版

积分式A/D转换器其它专用集成电路分册 清晰书签版
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