light1.c

实现LED的控制

#include <stdio.h>
#include <stdlib.h>

#include <Fx2.h>
#include <Fx2regs.h>

unsigned char flag;
unsigned char count_20;
unsigned char i, j ;//i is the index of DSP7LED
			 //j is the count of interrupt
unsigned char digbit;//BITTAB[digbit]

main()
{	
	OEA = 0xff;//sets the input/output direction
	OEB = 0xff;
  	
	IOA = 0xff;//set the initial number
	IOB = 0xff;
	
	TMOD = 0x11;//use two timers
	
	//set initial 50ms
	TL0 = 0xB0;
	TH0 = 0x3C;

	//1ms 
    TL1=0x18;    
    TH1=0xFC;
	
	EA = 1;//interrupt enable

	ET0 = 1;// timer0 enable
	ET1 = 1;

	TR0 = 1;//begin timer0
	TR1 = 1;
	
	
	while(1);//loop
}



void timer0(void) interrupt 1 using 0{
 	 TL0=0xB0;     
 	 TH0=0x3C;

 
 if(count_20<19){
  count_20++;
  flag=0;
 }else{
  count_20 = 0;
  flag = 1;
 }
 if(flag){
  if (j<7) j++;
  else j=0;
 }
}





void ledcontrol(void) interrupt 3 using 1
{
	
	unsigned char temp_DSP7LED[16];//add dp to the number
	unsigned char DSP7LED[16] = {0x3f, 0x06, 0x5b, 0x4f, 0x66, 0x6d, 0x7d, 0x07, 0x7f, 0x6f}; //ten numbers 0-9
	unsigned char BITTAB[8]={0x7F,0xBF,0xDF,0xEF,0xF7,0xFB,0xFD,0xFE};//8 LED enable
	


	
//	TH0 = (time/256);//put in the time again;
//	TL0 = (time%256);
	
	TL1=0x18;     //USED FOR AD SAMPLING
    TH1=0xFC;

	
	
//	if (j<7) j++;//每中断一次J就加1 显示就变一次
  //	else j=0;

//	do{
		switch(digbit+1)
		{
			case 1 : i = j%10;	break;
			case 2 : i = (j+1)%10;	break;
			case 3 : i = (j+2)%10;	break;
			case 4 : i = (j+3)%10;	break;
			case 5 : i = (j+4)%10;	break;
			case 6 : i = (j+5)%10;	break;
			case 7 : i = (j+6)%10;	break;
			case 8 : i = (j+7)%10;	break;
			default:;
		} 	
		//以下的是新加的小数点显示
		if(digbit==j)
			temp_DSP7LED[i] = 0x80 + DSP7LED[i];//dsp7led + 1000 0000
		else
			temp_DSP7LED[i] = DSP7LED[i];
		//小数点操作结束

		IOA = temp_DSP7LED[i];
		IOB = BITTAB[digbit];
		
		if(digbit<7)
			digbit = digbit+1;
		else 
			digbit = 0;//扫描显示
		
		
//	 }while(1);
	

}