📄 getnumber.java

📁 机械工业出版社的《jsp2.0动态网站开发实例指南》的源代码

💻 JAVA

字号:

//GetNumber.java
import java.io.*;
import java.util.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class GetNumber extends HttpServlet{
	public void init(ServletConfig config)throws ServletException{
		super.init(config);
	}
	public void doPost(HttpServletRequest request,HttpServletResponse response)throws ServletException,IOException{
		response.setContentType("text/html");
		ServletOutputStream out=response.getOutputStream();
		out.println("<html>");
		out.println("<head>");
		out.println("<title>GuessNumber</title>");
		out.println("</head>");
		out.println("<body>");
		out.println("<center><h1>");
		HttpSession session=request.getSession(true);
		out.println("欢迎来到猜数字游戏！随机生成一个1到100之间的整数，请你猜出来！");
		session.setAttribute("count",new Integer(0));
		session.setAttribute("number",new Integer((int)(Math.random()*100+1)));
		out.println("<form action=GetResult method=post name-form >");
		out.println("<input type=text name=number >");
		out.println("<input type=submit name=submit value=确定>");
		out.println("</form>");
		out.println("</h1></center>");
		out.println("</body>");
		out.println("</html>");
	}
	public void doGet(HttpServletRequest request,HttpServletResponse response)throws ServletException ,IOException{
		doPost(request,response);
	}
}

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