📄 power_out.mht
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Date: Tue, 12 May 2009 09:56:36 -0700
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<BODY><PRE>=BB power
A =3D 2 -1 0 0 y =3D 1
-1 2 -1 0 0
0 -1 2 -1 0
0 0 -1 2 0
Power Method Demonstration
Determine highest (1) or lowest (2) eigenvalue: 1
# 1 Lambda =3D 2.000000 Error =3D 50.000000
# 2 Lambda =3D 2.500000 Error =3D 20.000000
# 3 Lambda =3D 2.800000 Error =3D 10.714286
# 4 Lambda =3D 3.000000 Error =3D 6.666667
# 5 Lambda =3D 3.142857 Error =3D 4.545455
# 6 Lambda =3D 3.250000 Error =3D 3.296703
# 19 Lambda =3D 3.621001 Error =3D -0.031430
# 20 Lambda =3D 3.620179 Error =3D -0.022703
# 21 Lambda =3D 3.619585 Error =3D -0.016407
# 22 Lambda =3D 3.619156 Error =3D -0.011861
# 23 Lambda =3D 3.618846 Error =3D -0.008577
Highest eigenvalue is 0.381975
=BB power
Power Method Demonstration
Determine highest (1) or lowest (2) eigenvalue: 2
# 1 Lambda =3D 0.800000 Error =3D -25.000000
# 2 Lambda =3D 2.000000 Error =3D 60.000000
# 3 Lambda =3D 2.550000 Error =3D 21.568627
# 4 Lambda =3D 2.588235 Error =3D 1.477273
# 5 Lambda =3D 2.608333 Error =3D 0.770532
# 6 Lambda =3D 2.615161 Error =3D 0.261088
# 7 Lambda =3D 2.617215 Error =3D 0.078456
# 8 Lambda =3D 2.617804 Error =3D 0.022519
# 9 Lambda =3D 2.617970 Error =3D 0.006337
Lowest eigenvalue is 0.381975
=BB sort(eig(A))
ans =3D
0.3820
1.3820
2.6180
3.6180
</PRE></BODY></HTML>
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