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📄 stack.js

📁 这是一个ajax的例子大家好好的看看就是一个鱼眼的效果
💻 JS
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if(!dojo._hasResource["dojox.collections.Stack"]){ //_hasResource checks added by build. Do not use _hasResource directly in your code.dojo._hasResource["dojox.collections.Stack"] = true;dojo.provide("dojox.collections.Stack");dojo.require("dojox.collections._base");dojox.collections.Stack=function(/* array? */arr){	//	summary	//	returns an object of type dojox.collections.Stack	var q=[];	if (arr) q=q.concat(arr);	this.count=q.length;	this.clear=function(){		//	summary		//	Clear the internal array and reset the count		q=[];		this.count=q.length;	};	this.clone=function(){		//	summary		//	Create and return a clone of this Stack		return new dojox.collections.Stack(q);	};	this.contains=function(/* object */o){		//	summary		//	check to see if the stack contains object o		for (var i=0; i<q.length; i++){			if (q[i] == o){				return true;	//	bool			}		}		return false;	//	bool	};	this.copyTo=function(/* array */ arr, /* int */ i){		//	summary		//	copy the stack into array arr at index i		arr.splice(i,0,q);	};	this.forEach=function(/* function */ fn, /* object? */ scope){		//	summary		//	functional iterator, following the mozilla spec.		dojo.forEach(q, fn, scope);	};	this.getIterator=function(){		//	summary		//	get an iterator for this collection		return new dojox.collections.Iterator(q);	//	dojox.collections.Iterator	};	this.peek=function(){		//	summary		//	Return the next item without altering the stack itself.		return q[(q.length-1)];	//	object	};	this.pop=function(){		//	summary		//	pop and return the next item on the stack		var r=q.pop();		this.count=q.length;		return r;	//	object	};	this.push=function(/* object */ o){		//	summary		//	Push object o onto the stack		this.count=q.push(o);	};	this.toArray=function(){		//	summary		//	create and return an array based on the internal collection		return [].concat(q);	//	array	};}}

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