📄 d6r9.cpp
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#include <iostream.h>
#include <math.h>
#include <iomanip.h>
#include <stdlib.h>
static double r[98];
static int iff,ix1,ix2,ix3;
double ran1(int& idum)
{
double rm1,rm2,t;
int m1,m2,m3,ia1,ia2,ia3,ic1,ic2,ic3,j;
m1 = 259200, ia1 = 7141, ic1 = 54773, rm1 = 0.0000038580247,
m2 = 134456, ia2 = 8121, ic2 = 28411, rm2 = 0.0000074373773,
m3 = 243000, ia3= 4561, ic3 = 51349;
if ((idum < 0) || (iff == 0))
{
iff = 1;
ix1 = (ic1 - idum) % m1;
ix1 = (ia1 * ix1 + ic1) % m1;
ix2 = ix1 % m2;
ix1 = (ia1 * ix1 + ic1) % m1;
ix3 = ix1 % m3;
for (j = 1; j<=97; j++)
{
ix1 = (ia1 * ix1 + ic1)% m1;
ix2 = (ia2 * ix2 + ic2)% m2;
r[j] = (double(ix1) + double(ix2) * rm2) * rm1;
}
idum = 1;
}
ix1 = (ia1 * ix1 + ic1) % m1;
ix2 = (ia2 * ix2 + ic2) % m2;
ix3 = (ia3 * ix3 + ic3) % m3;
j = 1 + int((97 * ix3) / m3);
if ((j > 97) || (j < 1))
{
cout<< "abnormal exit"<<endl;
return 1;
}
t = r[j];
r[j] = (float(ix1) + float(ix2) * rm2) * rm1;
return t;
}
double gammln(double xx)
{
int j;
double temp;
double cof[6],stp,half,one,fpf,x,tmp,ser;
cof[1] = 76.18009173;
cof[2] = -86.50532033;
cof[3] = 24.01409822;
cof[4] = -1.231739516;
cof[5] = 0.00120858003;
cof[6] = -0.00000536382;
stp = 2.50662827465;
half = 0.5;
one = 1.0;
fpf = 5.5;
x = xx - one;
tmp = x + fpf;
tmp = (x + half) * log(tmp) - tmp;
ser = one;
for (j = 1;j<=6;j++)
{
x = x + one;
ser = ser + cof[j] / x;
}
temp = tmp + log(stp * ser);
return temp;
}
double bnldev(double pp, int n, int &idum)
{
int j,en,nold,bnl;
double p,am,g,t,oldg,pc,plog,pclog,pold,sq,y,em,pi;
pi = 3.141592654;
nold=0;
pold=0.0;
if (pp <= 0.5)
p = pp;
else
p = 1.0 - pp;
am = n * p;
if (n < 25)
{
bnl = 0;
for (j = 1; j<=n; j++)
if (ran1(idum) < p) bnl = bnl + 1;
}
else
{
if (am < 1.0)
{
g = exp(-am);
t = 1.0;
for (j = 0;j<=n;j++)
{
t = t * ran1(idum);
if (t < g) exit(1);
}
if (t >= g) j = n;
bnl = j;
}
else
{
if (n!= nold)
{
en = n;
oldg = gammln(en + 1.0);
nold = n;
}
if (p != pold)
{
pc = 1.0 - p;
plog = log(p);
pclog = log(pc);
pold = p;
}
sq = sqrt(2.0 * am * pc);
do
{
do
{
y = tan(pi * ran1(idum));
em = sq * y + am;
}
while ((em < 0) || (em >= en + 1.0));
em = int(em);
t = en - em;
t = exp(oldg-gammln(em+1.0)-gammln(t+1.0)+em*plog+t*pclog);
t = 1.2 * sq * (1.0 + y *y) * t;
}
while (ran1(idum) > t);
bnl = int(em);
}
}
if (p != pp) bnl = n - bnl;
t=bnl;
return t;
}
void main()
{
//program d6r9
//driver for routine bnldev
int idum,n = 20, npts = 10000, iscal = 200, llen = 50,nn=100,xm,klim,i,j,k,m;
double pp,dist[21];
char text[50];
idum = -133;
for (j = 1; j<=20; j++)
dist[j] = 0.0;
cout<<"Mean of Binomial distribution [n=1..20] -1 to end."<<endl;
xm = 5;
cout<<xm<<endl;
if (xm <= 0) exit(1);
pp=double(xm)/double(nn);
for (i = 1; i<=npts; i++)
{
j = int(bnldev(pp,nn, idum));
if ((j >= 0) && (j <= 20)) dist[j+1] = dist[j+1] + 1;
}
cout<< " x p[x] graph:"<<endl;
for (j = 1; j<=20; j++)
{
dist[j] = dist[j] / npts;
for (k = 0; k<=50; k++)
text[k] =' ';
klim = int(iscal * dist[j]);
if (klim > llen) klim = llen;
for (k = 1; k<=klim; k++)
text[k] = '*';
cout<< setw(5)<<float(j-1);
cout<< setw(10)<<dist[j]<<" ";
for (m = 1; m<=50; m++)
cout<< text[m];
cout<<endl;
}
}
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