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📁 23种算法C与JAVA实现 23种算法C与JAVA实现
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Date: Wed, 13 Sep 2006 01:07:38 +0800
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD><TITLE>=A6=D1=B9=AB=A8=AB=B0g=A9x=A1]=A4G=A1^</TITLE>
<META http-equiv=3DContent-Type content=3D"text/html; =
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<H3><A=20
href=3D"http://caterpillar.onlyfun.net/Gossip/index.html">http://caterpil=
lar.onlyfun.net/Gossip/index.html</A></H3>
<H1><A=20
href=3D"http://www.java3z.com/cwbwebhome/article/article3/AlgorithmGossip=
/AlgorithmGossip.htm">Algorithm=20
Gossip: =A6=D1=B9=AB=A8=AB=B0g=A9x=A1]=A4G=A1^</A></H1>
<H2>&nbsp;=BB=A1=A9=FA</H2>=A5=D1=A9=F3=B0g=AEc=AA=BA=B3]=ADp=A1A=A6=D1=B9=
=AB=A8=AB=B0g=AEc=AA=BA=A4J=A4f=A6=DC=A5X=A4f=B8=F4=AE|=A5i=AF=E0=A4=A3=A5=
u=A4@=B1=F8=A1A=A6p=A6=F3=A8D=A5X=A9=D2=A6=B3=AA=BA=B8=F4=AE|=A9O=A1H<BR>=

<H2>=B8=D1=AAk</H2>=A8D=A9=D2=A6=B3=B8=F4=AE|=AC=DD=B0_=A8=D3=BD=C6=C2=F8=
=A6=FD=A8=E4=B9=EA=A7=F3=C2=B2=B3=E6=A1A=A5u=ADn=A6b=A6=D1=B9=AB=A8=AB=A6=
=DC=A5X=A4f=AE=C9=C5=E3=A5=DC=B8g=B9L=AA=BA=B8=F4=AE|=A1A=B5M=AB=E1=B0h=A6=
^=A4W=A4@=AE=E6=AD=AB=B7s=BF=EF=BE=DC=A4U=A4@=AD=D3=A6=EC=B8m=C4~=C4=F2=BB=
=BC=B0j=B4N=A5i=A5H=A4F=A1A=A4=F1=A8D=A5X=B3=E6=A4@=B8=F4=AE|=C1=D9=C2=B2=
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N=A5i=A5H=A4F=A1C=20
<BR>
<H2>=BAt=BA=E2=AAk</H2><PRE>Procedure GO(maze[]) [<BR>    VISIT(maze, =
STARTI, STARTJ);<BR>]<BR>    <BR>Procedure VISIT(maze[], i, j) [<BR>    =
maze[i][j] =3D 1; <BR><BR>    IF(i =3D=3D ENDI AND j =3D=3D ENDJ) [<BR>  =
      // FIND A ROUTE, PRINT THE ROUTE<BR>    ]<BR><BR>    =
IF(maze[i][j+1] =3D=3D 0)<BR>        VISIT(maze, i, j+1); <BR>    =
IF(maze[i+1][j] =3D=3D 0)<BR>        VISIT(maze, i+1, j); <BR>    =
IF(maze[i][j-1] =3D=3D 0)<BR>        VISIT(maze, i, j-1); <BR>    =
if(maze[i-1][j] =3D=3D 0)<BR>        VISIT(maze, i-1, j); <BR><BR>    =
maze[i][j] =3D 0; <BR>] <BR></PRE>
<H2>=B9=EA=A7@</H2>
<UL>
  <LI>C </LI></UL><PRE>#include &lt;stdio.h&gt;<BR>#include =
&lt;stdlib.h&gt; <BR><BR>void visit(int, int);<BR><BR>int maze[9][9] =3D =
{{2, 2, 2, 2, 2, 2, 2, 2, 2},<BR>                  {2, 0, 0, 0, 0, 0, 0, =
0, 2},<BR>                  {2, 0, 2, 2, 0, 2, 2, 0, 2},<BR>             =
     {2, 0, 2, 0, 0, 2, 0, 0, 2},<BR>                  {2, 0, 2, 0, 2, =
0, 2, 0, 2},<BR>                  {2, 0, 0, 0, 0, 0, 2, 0, 2},<BR>       =
           {2, 2, 0, 2, 2, 0, 2, 2, 2},<BR>                  {2, 0, 0, =
0, 0, 0, 0, 0, 2},<BR>                  {2, 2, 2, 2, 2, 2, 2, 2, =
2}};<BR><BR>int startI =3D 1, startJ =3D 1;  // =A4J=A4f<BR>int endI =3D =
7, endJ =3D 7;  // =A5X=A4f<BR><BR>int main(void) { <BR>    int i, j; =
<BR><BR>    printf("=C5=E3=A5=DC=B0g=AEc=A1G\n"); <BR>    for(i =3D 0; i =
&lt; 7; i++) { <BR>        for(j =3D 0; j &lt; 7; j++) <BR>            =
if(maze[i][j] =3D=3D 2) <BR>                printf("=A2i"); <BR>         =
   else <BR>                printf("  "); <BR>        printf("\n"); <BR> =
   } <BR><BR>    visit(startI, startJ);<BR><BR>    return 0; <BR>} =
<BR><BR>void visit(int i, int j) {<BR>    int m, n;<BR><BR>    =
maze[i][j] =3D 1; <BR><BR>    if(i =3D=3D endI &amp;&amp; j =3D=3D endJ) =
{<BR>        printf("\n=C5=E3=A5=DC=B8=F4=AE|=A1G\n");<BR>        for(m =
=3D 0; m &lt; 9; m++) {<BR>            for(n =3D 0; n &lt; 9; n++)<BR>   =
             if(maze[m][n] =3D=3D 2)<BR>                    =
printf("=A2i");<BR>                else if(maze[m][n] =3D=3D 1)<BR>      =
              printf("=A1=BA");<BR>                else<BR>              =
      printf("  ");<BR>            printf("\n");<BR>        }<BR>    =
}<BR><BR>    if(maze[i][j+1] =3D=3D 0) visit(i, j+1);<BR>    =
if(maze[i+1][j] =3D=3D 0) visit(i+1, j);<BR>    if(maze[i][j-1] =3D=3D =
0) visit(i, j-1);<BR>    if(maze[i-1][j] =3D=3D 0) visit(i-1, =
j);<BR><BR>    maze[i][j] =3D 0;<BR>}  <BR></PRE><BR>
<UL>
  <LI>Java </LI></UL><PRE>public class Mouse {<BR>    private int =
startI, startJ;  // =A4J=A4f <BR>    private int endI, endJ;  // =
=A5X=A4f<BR>    <BR>    public static void main(String[] args) {<BR>     =
   int maze[][] =3D {{2, 2, 2, 2, 2, 2, 2, 2, 2},<BR>                    =
    {2, 0, 0, 0, 0, 0, 0, 0, 2},<BR>                        {2, 0, 2, 2, =
0, 2, 2, 0, 2},<BR>                        {2, 0, 2, 0, 0, 2, 0, 0, =
2},<BR>                        {2, 0, 2, 0, 2, 0, 2, 0, 2},<BR>          =
              {2, 0, 0, 0, 0, 0, 2, 0, 2},<BR>                        =
{2, 2, 0, 2, 2, 0, 2, 2, 2},<BR>                        {2, 0, 0, 0, 0, =
0, 0, 0, 2},<BR>                        {2, 2, 2, 2, 2, 2, 2, 2, =
2}};<BR>        <BR>        =
System.out.println("=C5=E3=A5=DC=B0g=AEc=A1G"); <BR>        for(int i =
=3D 0; i &lt; maze.length; i++) { <BR>            for(int j =3D 0; j =
&lt; maze[0].length; j++) <BR>                if(maze[i][j] =3D=3D 2) =
<BR>                    System.out.print("=A2i"); <BR>                =
else <BR>                    System.out.print("  "); <BR>            =
System.out.println(); <BR>        }<BR><BR>        Mouse mouse =3D new =
Mouse();<BR>        mouse.setStart(1, 1);<BR>        mouse.setEnd(7, =
7);<BR>        <BR>        mouse.go(maze);<BR>    }<BR>    <BR>    =
public void setStart(int i, int j) {<BR>        this.startI =3D i;<BR>   =
     this.startJ =3D j;<BR>    }<BR>    <BR>    public void setEnd(int =
i, int j) {<BR>        this.endI =3D i;<BR>        this.endJ =3D j;<BR>  =
  }<BR>    <BR>    public void go(int[][] maze) {<BR>        visit(maze, =
startI, startJ);<BR>    }<BR>    <BR>    private void visit(int[][] =
maze, int i, int j) {<BR>        maze[i][j] =3D 1; <BR><BR>        if(i =
=3D=3D endI &amp;&amp; j =3D=3D endJ) {<BR>            =
System.out.println("\n=A7=E4=A8=EC=A5X=A4f=A1I");<BR>            for(int =
m =3D 0; m &lt; maze.length; m++) { <BR>                for(int n =3D 0; =
n &lt; maze[0].length; n++) { <BR>                    if(maze[m][n] =
=3D=3D 2) <BR>                        System.out.print("=A2i"); <BR>     =
               else if(maze[m][n] =3D=3D 1) <BR>                        =
System.out.print("=A1=BA"); <BR>                    else <BR>            =
            System.out.print("  "); <BR>                } <BR>           =
     System.out.println();<BR>            }<BR>        }<BR><BR>        =
if(maze[i][j+1] =3D=3D 0) <BR>            visit(maze, i, j+1); <BR>      =
  if(maze[i+1][j] =3D=3D 0)<BR>            visit(maze, i+1, j); <BR>     =
   if(maze[i][j-1] =3D=3D 0)<BR>            visit(maze, i, j-1); <BR>    =
    if(maze[i-1][j] =3D=3D 0)<BR>            visit(maze, i-1, j); <BR>   =
    <BR>        maze[i][j] =3D 0;<BR>    }<BR>}</PRE><BR></BODY></HTML>

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