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📁 23种算法C与JAVA实现 23种算法C与JAVA实现
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Date: Wed, 13 Sep 2006 01:05:48 +0800
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD><TITLE>=A6=D1=B9=AB=A8=AB=B0g=A9x=A1]=A4@=A1^</TITLE>
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<H3><A=20
href=3D"http://caterpillar.onlyfun.net/Gossip/index.html">http://caterpil=
lar.onlyfun.net/Gossip/index.html</A></H3>
<H1><A=20
href=3D"http://www.java3z.com/cwbwebhome/article/article3/AlgorithmGossip=
/AlgorithmGossip.htm">Algorithm=20
Gossip: =A6=D1=B9=AB=A8=AB=B0g=A9x=A1]=A4@=A1^</A></H1>
<H2>&nbsp;=BB=A1=A9=FA</H2>=A6=D1=B9=AB=A8=AB=B0g=AEc=ACO=BB=BC=B0j=A8D=B8=
=D1=AA=BA=B0=F2=A5=BB=C3D=AB=AC=A1A=A7=DA=AD=CC=A6b=A4G=BA=FB=B0}=A6C=A4=A4=
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D=A5X=A5=D1=A4J=A4f=A6=DC=A5X=A4f=AA=BA=B8=F4=AE|=A1C<BR>
<H2>=B8=D1=AAk</H2>=A6=D1=B9=AB=AA=BA=A8=AB=AAk=A6=B3=A4W=A1B=A5=AA=A1B=A4=
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<BR><BR>
<H2>=BAt=BA=E2=AAk</H2><PRE>Procedure GO(maze[]) [<BR>    VISIT(maze, =
STARTI, STARTJ);<BR>]<BR>    <BR>Procedure VISIT(maze[], i, j) [<BR>    =
maze[i][j] =3D 1; <BR><BR>    IF(i =3D=3D ENDI AND j =3D=3D ENDJ) <BR>   =
     success =3D TRUE; <BR><BR>    IF(success !=3D TRUE AND maze[i][j+1] =
=3D=3D 0)<BR>        VISIT(maze, i, j+1); <BR>    IF(success !=3D TRUE =
AND maze[i+1][j] =3D=3D 0)<BR>        VISIT(maze, i+1, j); <BR>    =
IF(success !=3D TRUE AND maze[i][j-1] =3D=3D 0)<BR>        VISIT(maze, =
i, j-1); <BR>    if(success !=3D TRUE AND maze[i-1][j] =3D=3D 0)<BR>     =
   VISIT(maze, i-1, j); <BR><BR>    IF(success !=3D TRUE) <BR>        =
maze[i][j] =3D 0; <BR>] <BR></PRE>
<H2>=B9=EA=A7@</H2>
<UL>
  <LI>C </LI></UL><PRE>#include &lt;stdio.h&gt;<BR>#include =
&lt;stdlib.h&gt; <BR><BR>int visit(int, int); <BR><BR>int maze[7][7] =3D =
{{2, 2, 2, 2, 2, 2, 2}, <BR>                  {2, 0, 0, 0, 0, 0, 2}, =
<BR>                  {2, 0, 2, 0, 2, 0, 2}, <BR>                  {2, =
0, 0, 2, 0, 2, 2}, <BR>                  {2, 2, 0, 2, 0, 2, 2}, <BR>     =
             {2, 0, 0, 0, 0, 0, 2}, <BR>                  {2, 2, 2, 2, =
2, 2, 2}}; <BR><BR>int startI =3D 1, startJ =3D 1;  // =A4J=A4f<BR>int =
endI =3D 5, endJ =3D 5;  // =A5X=A4f<BR>int success =3D 0;<BR><BR>int =
main(void) { <BR>    int i, j; <BR><BR>    =
printf("=C5=E3=A5=DC=B0g=AEc=A1G\n"); <BR>    for(i =3D 0; i &lt; 7; =
i++) { <BR>        for(j =3D 0; j &lt; 7; j++) <BR>            =
if(maze[i][j] =3D=3D 2) <BR>                printf("=A2i"); <BR>         =
   else <BR>                printf("  "); <BR>        printf("\n"); <BR> =
   } <BR><BR>    if(visit(startI, startJ) =3D=3D 0)<BR>        =
printf("\n=A8S=A6=B3=A7=E4=A8=EC=A5X=A4f=A1I\n"); <BR>    else { <BR>    =
    printf("\n=C5=E3=A5=DC=B8=F4=AE|=A1G\n"); <BR>        for(i =3D 0; i =
&lt; 7; i++) { <BR>            for(j =3D 0; j &lt; 7; j++) { <BR>        =
        if(maze[i][j] =3D=3D 2) <BR>                    printf("=A2i"); =
<BR>                else if(maze[i][j] =3D=3D 1) <BR>                    =
printf("=A1=BA"); <BR>                else <BR>                    =
printf("  "); <BR>            } <BR>            printf("\n"); <BR>       =
 } <BR>    } <BR><BR>    return 0; <BR>} <BR><BR>int visit(int i, int j) =
{ <BR>    maze[i][j] =3D 1; <BR><BR>    if(i =3D=3D endI &amp;&amp; j =
=3D=3D endJ)<BR>        success =3D 1; <BR><BR>    if(success !=3D 1 =
&amp;&amp; maze[i][j+1] =3D=3D 0) visit(i, j+1); <BR>    if(success !=3D =
1 &amp;&amp; maze[i+1][j] =3D=3D 0) visit(i+1, j); <BR>    if(success =
!=3D 1 &amp;&amp; maze[i][j-1] =3D=3D 0) visit(i, j-1); <BR>    =
if(success !=3D 1 &amp;&amp; maze[i-1][j] =3D=3D 0) visit(i-1, j); =
<BR><BR>    if(success !=3D 1) <BR>        maze[i][j] =3D 0; <BR>    =
<BR>    return success; <BR>}  <BR></PRE><BR>
<UL>
  <LI>Java </LI></UL><PRE>public class Mouse {<BR>    private int =
startI, startJ;  // =A4J=A4f <BR>    private int endI, endJ;  // =
=A5X=A4f<BR>    private boolean success =3D false;<BR>    <BR>    public =
static void main(String[] args) {<BR>        int[][] maze =3D {{2, 2, 2, =
2, 2, 2, 2}, <BR>                        {2, 0, 0, 0, 0, 0, 2}, <BR>     =
                   {2, 0, 2, 0, 2, 0, 2}, <BR>                        =
{2, 0, 0, 2, 0, 2, 2}, <BR>                        {2, 2, 0, 2, 0, 2, =
2}, <BR>                        {2, 0, 0, 0, 0, 0, 2}, <BR>              =
          {2, 2, 2, 2, 2, 2, 2}};<BR>        <BR>        =
System.out.println("=C5=E3=A5=DC=B0g=AEc=A1G"); <BR>        for(int i =
=3D 0; i &lt; maze.length; i++) { <BR>            for(int j =3D 0; j =
&lt; maze[0].length; j++) <BR>                if(maze[i][j] =3D=3D 2) =
<BR>                    System.out.print("=A2i"); <BR>                =
else <BR>                    System.out.print("  "); <BR>            =
System.out.println(); <BR>        }<BR><BR>        Mouse mouse =3D new =
Mouse();<BR>        mouse.setStart(1, 1);<BR>        mouse.setEnd(5, =
5);<BR>        <BR>        if(!mouse.go(maze)) {<BR>            =
System.out.println("\n=A8S=A6=B3=A7=E4=A8=EC=A5X=A4f=A1I");<BR>        =
}<BR>        else {<BR>            =
System.out.println("\n=A7=E4=A8=EC=A5X=A4f=A1I");<BR>            for(int =
i =3D 0; i &lt; maze.length; i++) { <BR>                for(int j =3D 0; =
j &lt; maze[0].length; j++) { <BR>                    if(maze[i][j] =
=3D=3D 2) <BR>                        System.out.print("=A2i"); <BR>     =
               else if(maze[i][j] =3D=3D 1) <BR>                        =
System.out.print("=A1=BA"); <BR>                    else <BR>            =
            System.out.print("  "); <BR>                } <BR>           =
     System.out.println(); <BR>            }            <BR>        =
}<BR>    }<BR>    <BR>    public void setStart(int i, int j) {<BR>       =
 this.startI =3D i;<BR>        this.startJ =3D j;<BR>    }<BR>    <BR>   =
 public void setEnd(int i, int j) {<BR>        this.endI =3D i;<BR>      =
  this.endJ =3D j;<BR>    }<BR>    <BR>    public boolean go(int[][] =
maze) {<BR>        return visit(maze, startI, startJ);<BR>    }<BR>    =
<BR>    private boolean visit(int[][] maze, int i, int j) {<BR>        =
maze[i][j] =3D 1; <BR><BR>        if(i =3D=3D endI &amp;&amp; j =3D=3D =
endJ) <BR>            success =3D true; <BR><BR>        if(!success =
&amp;&amp; maze[i][j+1] =3D=3D 0) <BR>            visit(maze, i, j+1); =
<BR>        if(!success &amp;&amp; maze[i+1][j] =3D=3D 0)<BR>            =
visit(maze, i+1, j); <BR>        if(!success &amp;&amp; maze[i][j-1] =
=3D=3D 0)<BR>            visit(maze, i, j-1); <BR>        if(!success =
&amp;&amp; maze[i-1][j] =3D=3D 0)<BR>            visit(maze, i-1, j); =
<BR><BR>        if(!success) <BR>            maze[i][j] =3D 0; <BR>      =
  <BR>        return success; <BR>    }<BR>} </PRE><BR></BODY></HTML>

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