data

ECLIPSE 3.3工程. AES算法的应用.

Input  (hex)     = 32 43 f6 a8 88 5a 30 8d 31 31 98 a2 e0 37 07 34  
Cipher Key (hex) = 2b 7e 15 16 28 ae d2 a6 ab f7 15 88 09 cf 4f 3c

0x32 0x43 0xf6 0xa8 0x88 0x5a 0x30 0x8d 0x31 0x31 0x98 0xa2 0xe0 0x37 0x07 0x34
Input:
0x00 0x11 0x22 0x33 0x44 0x55 0x66 0x77 0x88 0x99 0xaa 0xbb 0xcc 0xdd 0xee 0xff
PLAINTEXT: 00112233445566778899aabbccddeeff
KEY: 000102030405060708090a0b0c0d0e0f
CIPHER (ENCRYPT):
round[ 0].input 00112233445566778899aabbccddeeff
round[ 0].k_sch 000102030405060708090a0b0c0d0e0f
round[ 1].start 00102030405060708090a0b0c0d0e0f0
round[ 1].s_box 63cab7040953d051cd60e0e7ba70e18c
round[ 1].s_row 6353e08c0960e104cd70b751bacad0e7
round[ 1].m_col 5f72641557f5bc92f7be3b291db9f91a
round[ 1].k_sch d6aa74fdd2af72fadaa678f1d6ab76fe