cards.cs

1．中间纸牌的最左面由一张Flip牌

using System;
using System.Collections.Generic;
using System.Text;

namespace QuickSpark
{
    class Cards
    { 
       /*private static int Itimes = 0;
        GameForm form;
        public cards(GameForm form)
        {
            this.form = form;
        }
        public void play()
        {
               //系统会每隔一段时间调用下面的函数 要玩游戏~~~
            //生成机器人手中牌的随机数
            Random Rnumber = new Random();
            int Nnum = Rnumber.Next(1, 14);
            //生成随机数来显示箭头的变量
            int Iarrowhead = Rnumber.Next(1, 3);
            //这是覆盖牌的中间数 用来记录覆盖牌的数值以便覆盖和修改
            int p1, p2, p3, p4, q1, q2, q3, q4 = 0;
            int[] Form1.getup 
            int[] cardsCards=form.getUpCards();
            int[] midCards=form.getMidCards();
            //IF是验证当第一个箭头为上 并且电脑手中4张牌中有牌比TEMP1的数字大的情况
            
            if (!form.getUp1Status() && ((cardsCards[0] > midCards[0]) || (cardsCards[1] > midCards[0]) || (cardsCards[2] > midCards[0]) ||
                (cardsCards[3]) > midCards[0]))
                {
                    //把最大的数字覆盖TEMP1.TEXT
                    q1 = Math.Max(Math.Max(cardsCards[0], cardsCards[1]), Math.Max(cardsCards[2], cardsCards[3]));
                    form.setMid1Card(q1);
                //生成新的电脑手中的刚使用的牌的随机数 覆盖旧牌 
                    Nnum = Rnumber.Next(1, 14);
                    if (q1 == cardsCards[0])
                    {
                        Nnum = Rnumber.Next(1, 14);
                        form.setcards1Card(Nnum);
                    }
                    if (q1 == cardsCards[1])
                    {
                        Nnum = Rnumber.Next(1, 14);
                        form.setcards2Card(Nnum);
                    }
                    if (q1 == cardsCards[2])
                    {
                        Nnum = Rnumber.Next(1, 14);
                        form.setcards3Card(Nnum);
                    }
                    if (q1 == cardsCards[3])
                    {
                        Nnum = Rnumber.Next(1, 14);
                        form.setcards4Card(Nnum);
                    }
                    //修改箭头 随机上下
                    //form.initUpArrow();
                    //数字加一 记录已经成功修改牌一次
                    Itimes++;
                    form.ChangPic(); 
                }
                //当上一中情况不满足 就使用下一中情况 一共有9个情况 最后一个情况是当没牌可出的时候电脑自动洗牌 下面都是IF-ELSE类推 
                //表明了每隔X秒 机器人只会移动其中一张牌 并且机器人是按一定顺序要检查 这样降低难度 避免出现20张牌一次性全部使用完毕而造成
                //玩家心理上和生理上的重大负担！
                else
                {
                    if (!form.getUp2Status() && ((cardsCards[0] > midCards[1]) || (cardsCards[1] > midCards[1]) || (cardsCards[2] > midCards[1]) ||
                (cardsCards[3]) > midCards[1]))
                    {

                        q2 = Math.Max(Math.Max(cardsCards[0], cardsCards[1]), Math.Max(cardsCards[2], cardsCards[3]));
                        form.setMid1Card(q2);
                        //生成新的电脑手中的刚使用的牌的随机数 覆盖旧牌 
                        Nnum = Rnumber.Next(1, 14);
                        if (q2 == cardsCards[0])
                        {
                            Nnum = Rnumber.Next(1, 14);
                            form.setcards1Card(Nnum);
                        }
                        if (q2 == cardsCards[1])
                        {
                            Nnum = Rnumber.Next(1, 14);
                            form.setcards2Card(Nnum);
                        }
                        if (q2 == cardsCards[2])
                        {
                            Nnum = Rnumber.Next(1, 14);
                            form.setcards3Card(Nnum);
                        }
                        if (q2 == cardsCards[3])
                        {
                            Nnum = Rnumber.Next(1, 14);
                            form.setcards4Card(Nnum);
                        }

                        //form.initUpArrow();
                        Itimes++;
                        form.ChangPic();
                    }
                    else
                    {
                        if (!form.getUp1Status() && ((cardsCards[0] > midCards[2]) || (cardsCards[1] > midCards[2]) || (cardsCards[2] > midCards[2]) ||
                        (cardsCards[3]) > midCards[2]))
                        {
                            q3 = Math.Max(Math.Max(cardsCards[0], cardsCards[1]), Math.Max(cardsCards[2], cardsCards[3]));
                            form.setMid1Card(q3);
                            //生成新的电脑手中的刚使用的牌的随机数 覆盖旧牌 
                            Nnum = Rnumber.Next(1, 14);
                            if (q3 == cardsCards[0])
                            {
                                Nnum = Rnumber.Next(1, 14);
                                form.setcards1Card(Nnum);
                            }
                            if (q3 == cardsCards[1])
                            {
                                Nnum = Rnumber.Next(1, 14);
                                form.setcards2Card(Nnum);
                            }
                            if (q3 == cardsCards[2])
                            {
                                Nnum = Rnumber.Next(1, 14);
                                form.setcards3Card(Nnum);
                            }
                            if (q3 == cardsCards[3])
                            {
                                Nnum = Rnumber.Next(1, 14);
                                form.setcards4Card(Nnum);
                            }
                            //form.initUpArrow();
                            Itimes++;
                            form.ChangPic();
                        }
                        else
                        {
                            if (!form.getUp1Status() && ((cardsCards[0] > midCards[3]) || (cardsCards[1] > midCards[3]) || (cardsCards[2] > midCards[3]) ||
                (cardsCards[3]) > midCards[3]))
                            {

                                q4 = Math.Max(Math.Max(cardsCards[0], cardsCards[1]), Math.Max(cardsCards[2], cardsCards[3]));
                                form.setMid1Card(q4);
                                //生成新的电脑手中的刚使用的牌的随机数 覆盖旧牌 
                                Nnum = Rnumber.Next(1, 14);
                                if (q4 == cardsCards[0])
                                {
                                    Nnum = Rnumber.Next(1, 14);
                                    form.setcards1Card(Nnum);
                                }
                                if (q4 == cardsCards[1])
                                {
                                    Nnum = Rnumber.Next(1, 14);
                                    form.setcards2Card(Nnum);
                                }
                                if (q4 == cardsCards[2])
                                {
                                    Nnum = Rnumber.Next(1, 14);
                                    form.setcards3Card(Nnum);
                                }
                                if (q4 == cardsCards[3])
                                {
                                    Nnum = Rnumber.Next(1, 14);
                                    form.setcards4Card(Nnum);