f0.m

语音处理平台 可以分析语音能量 第一振峰频率等数据

a=[  
307.6923  
307.6923  
307.6923  
307.6923  
307.6923  
307.6923  
307.6923

  
307.6923  
307.6923  
307.6923  

307.6923  
307.6923  
307.6923  
307.6923
  307.6923
  307.6923
  
  307.6923 
  307.6923 
  307.6923 
  307.6923 
  307.6923
  210.5263 
  210.5263  
  216.2162  
  258.0645  
  266.6667  
  266.6667  
  266.6667

  266.6667 
  258.0645  
  258.0645  
  258.0645  
  258.0645        
  0         
  0
  0      
  0 
         228.5714 
         250.0000 
         258.0645 
         266.6667  
         266.6667
  266.6667 
  266.6667  
  258.0645  
  250.0000  
  242.4242  
  242.4242  
  235.2941
  228.5714  
  228.5714  
  222.2222  
  216.2162  
  210.5263  
  210.5263 
  205.1282
  205.1282  
  205.1282  
  285.7143  
  285.7143  
  285.7143  
  285.7143  
  266.6667
   170.2128 
   216.2162        
   0  
   216.2162 
   307.6923 
   307.6923  
  

    ];

n=length(a);

m=sum(a)/n    %平均值

b=max(a)-min(a)  %范围


c=0;
for i=1:n-1,
   %for j=1:6,
        c(i)=a(i+1)-a(i);
    %end    
%    c(i,j+1)=a(i+1,1)-a(i,j+1);
end    
d=sum(abs(c))/(n-1)