f0.asv

语音处理平台 可以分析语音能量 第一振峰频率等数据

a=[  
307.6923  
307.6923  
307.6923  
307.6923  
307.6923  
307.6923  
307.6923

  
307.6923  
307.6923  
307.6923  

307.6923  
307.6923  
307.6923  
307.6923
  307.6923
  307.6923
  
  307.6923 
  307.6923 
  307.6923 
  307.6923 
  307.6923

  307.6923 
  307.6923  307.6923  307.6923  307.6923  307.6923  307.6923
 

  307.6923  307.6923  307.6923  307.6923  307.6923  307.6923  307.6923

  Columns 57 through 63 

  
  
  210.5263 
  210.5263  
  216.2162  
  258.0645  
  266.6667  
  266.6667  
  266.6667

  266.6667 
  258.0645  
  258.0645  
  258.0645  
  258.0645        
  0         
  0

 
  
         0        
         0 
         228.5714 
         250.0000 
         258.0645 
         266.6667  
         266.6667
  266.6667 
  266.6667  
  258.0645  
  250.0000  
  242.4242  
  242.4242  
  235.2941
  228.5714  
  228.5714  
  222.2222  
  216.2162  
  210.5263  
  210.5263 
  205.1282
  205.1282  
  205.1282  
  285.7143  
  285.7143  
  285.7143  
  285.7143  
  266.6667

  Columns 120 through 126 

  170.2128  216.2162         0  216.2162  307.6923  307.6923  307.6923

  Columns 127 through 133 

  307.6923  307.6923  307.6923  307.6923  307.6923  307.6923  307.6923

  Columns 134 through 140 

  307.6923  307.6923  307.6923  307.6923  307.6923  307.6923  307.6923

  Columns 141 through 147 

  307.6923  307.6923  307.6923  307.6923  307.6923  307.6923  307.6923

  

    ];

n=length(a);

m=sum(a)/n    %平均值

b=max(a)-min(a)  %范围


c=0;
for i=1:n-1,
   %for j=1:6,
        c(i)=a(i+1)-a(i);
    %end    
%    c(i,j+1)=a(i+1,1)-a(i,j+1);
end    
d=sum(abs(c))/(n-1)